a. Is this population in Hardy-Weinberg equilibrium? What evidence do you have to support your decision?

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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4. Hardy-Weinberg Equilibrium
A population is in Hardy-Weinberg equilibrium (HWE) if the allele frequencies are not
changing over time. Refer to the calculations you made from the table in question 1 of
Part A of this lesson 1 assignment.
a. Is this population in Hardy-Weinberg equilibrium? What evidence do you have to
support your decision?
Answer:
b. Review the five conditions for Hardy-Weinberg equilibrium. From what you know
about this population, what is one reason it could not be in HWE?
Answer:
Transcribed Image Text:4. Hardy-Weinberg Equilibrium A population is in Hardy-Weinberg equilibrium (HWE) if the allele frequencies are not changing over time. Refer to the calculations you made from the table in question 1 of Part A of this lesson 1 assignment. a. Is this population in Hardy-Weinberg equilibrium? What evidence do you have to support your decision? Answer: b. Review the five conditions for Hardy-Weinberg equilibrium. From what you know about this population, what is one reason it could not be in HWE? Answer:
f(B) allele =-
# of B alleles
total # of alleles ( = 20)
Example:
2000
2005
Phenotype Frequencies
8/10
= 0.8
8/10
= 0.8
f(black)
2/10
= 0.2
2/10
= 0.2
f(white)
Genotype Frequencies
3/10
7/10
= 0.7
f(BB)
=0.3
5/10
1/10
= 0.1
f(Bb)
=0.5
2/10
= 0.2
2/10
f(bb)
=0.2
Allele Frequencies
15/20
f(B)
11/20
= 0.20
= 0.75
9/20
5/20
= 0.25
f(b)
= 0.45
Transcribed Image Text:f(B) allele =- # of B alleles total # of alleles ( = 20) Example: 2000 2005 Phenotype Frequencies 8/10 = 0.8 8/10 = 0.8 f(black) 2/10 = 0.2 2/10 = 0.2 f(white) Genotype Frequencies 3/10 7/10 = 0.7 f(BB) =0.3 5/10 1/10 = 0.1 f(Bb) =0.5 2/10 = 0.2 2/10 f(bb) =0.2 Allele Frequencies 15/20 f(B) 11/20 = 0.20 = 0.75 9/20 5/20 = 0.25 f(b) = 0.45
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