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A. Given the per unit equivalent circuit below, solve for V2 in per unit. I P₁=0.8 p.u. PF-0.9 lag V₁=1.0 p.u. ₁ VO 0.03+10.04 0.045+10.06 m P₁=1.2 p.u. PF=0.95 lag V₂

A. Given the per unit equivalent circuit below, solve for V2 in per unit. I P₁=0.8 p.u. PF-0.9 lag V₁=1.0 p.u. ₁ VO 0.03+10.04 0.045+10.06 m P₁=1.2 p.u. PF=0.95 lag V₂

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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A. Given the per unit equivalent circuit below, solve for V2 in per unit. I P₁=0.8 p.u. PF=0.9 lag ₁ V₁=1.0 p.u. 0.03+10.04 0.045+10.06 Answer: V2=0.9833 angle 0.2217 degrees P₁=1.2 p.u. PF=0.95 lag ~V₂ haun halow and show all param
Transcribed Image Text:A. Given the per unit equivalent circuit below, solve for V2 in per unit. I P₁=0.8 p.u. PF=0.9 lag ₁ V₁=1.0 p.u. 0.03+10.04 0.045+10.06 Answer: V2=0.9833 angle 0.2217 degrees P₁=1.2 p.u. PF=0.95 lag ~V₂ haun halow and show all param
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