a. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. Confidence interval= b. Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

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### Confidence Interval Calculation for Grocery Spending Survey

In a survey of 151 households, a Food Marketing Institute found that 53 households spend more than $125 a week on groceries. To find the 90% confidence interval for the true proportion of households that spend more than $125 a week on groceries, you need to select the appropriate calculator from the options below:

1. Confidence Interval for a Population Proportion
2. Confidence Interval for a Population Mean Given Statistics
3. Hypothesis Test for a Population Mean Given Statistics
4. Two Independent Sample Means Comparison Given Data
5. Chi-Square Test for Goodness of Fit
6. Chi-Square Test for Independence
7. Two Independent Sample Means Comparison Given Statistics
8. One-Way ANOVA
9. **Confidence Interval for a Population Mean Given Data** (incorrect selection)
10. Hypothesis Test for a Population Proportion
11. Two Dependent Sample Means Comparison Given Data
12. Hypothesis Test for a Population Mean Given Data
13. Two Independent Proportions Comparison

The correct selection should be **Confidence Interval for a Population Proportion**. This choice is essential because the data involves determining a proportion of households fitting a certain spending category.

### Tasks:
a. **Enter your answer as an open-interval** using decimals (not percents) accurate to three decimal places:
   - Confidence interval = (____, ____)

b. **Express the same answer as a tri-linear inequality** using decimals (not percents) accurate to three decimal places:
   - ____ < p < ____

c. **Express the same answer using the point estimate and margin of error**. Provide your answers as decimals, to three places:
   - p = ____ ± ____

This framework guides users through calculating and interpreting the confidence interval accurately.
Transcribed Image Text:### Confidence Interval Calculation for Grocery Spending Survey In a survey of 151 households, a Food Marketing Institute found that 53 households spend more than $125 a week on groceries. To find the 90% confidence interval for the true proportion of households that spend more than $125 a week on groceries, you need to select the appropriate calculator from the options below: 1. Confidence Interval for a Population Proportion 2. Confidence Interval for a Population Mean Given Statistics 3. Hypothesis Test for a Population Mean Given Statistics 4. Two Independent Sample Means Comparison Given Data 5. Chi-Square Test for Goodness of Fit 6. Chi-Square Test for Independence 7. Two Independent Sample Means Comparison Given Statistics 8. One-Way ANOVA 9. **Confidence Interval for a Population Mean Given Data** (incorrect selection) 10. Hypothesis Test for a Population Proportion 11. Two Dependent Sample Means Comparison Given Data 12. Hypothesis Test for a Population Mean Given Data 13. Two Independent Proportions Comparison The correct selection should be **Confidence Interval for a Population Proportion**. This choice is essential because the data involves determining a proportion of households fitting a certain spending category. ### Tasks: a. **Enter your answer as an open-interval** using decimals (not percents) accurate to three decimal places: - Confidence interval = (____, ____) b. **Express the same answer as a tri-linear inequality** using decimals (not percents) accurate to three decimal places: - ____ < p < ____ c. **Express the same answer using the point estimate and margin of error**. Provide your answers as decimals, to three places: - p = ____ ± ____ This framework guides users through calculating and interpreting the confidence interval accurately.
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