A. Compute the degree of saturation. B. Compute the air void ratio

Q: x=5

A:

Q: 3. A soil has a liquid limit of 61 and a plastic limit of 30. A moisture content test performed on…

A: Given : Liquid Limit = 61 Plastic Limit = 30  Mass of soil can before placing in oven = 96.20 g mass…

Q: Result II. Construct the bending moment diagram of the following structure. Reviewer 8kN 6kN/m A 2m…

A: The algebraic sum of the vertical forces at any section of a beam to the right or left of the…

Q: 0.1.A A soil specimen have void ratio (e) of 0.7, Gs 2.72. Calculate the total unit weight, dry unit…

A: A) Given that soil specimen is having  Void ratio (e) = 0.7 Specific Gravity (Gs) = 2.72 Degree of…

Q: 2. The following laboratory test results for Atterberg limits and particle-size distribution (sieve…

A:

Q: Following are the results from the liquid and plastic limit test for a soil Plastic limit = 12.2%…

A: Plastic limit=12.2% Moisture content=26.5%

Q: A 0.082-m3 sample of soil weighs 1.445kN. When it is dried out in an oven, it weighs 1.301kN. The…

A:

Q: A liquid limit test performed on a soil sample has the

A: here water content is given to us and also N = 20

Q: Classify the soil sample using AASHTO Classification System. Passing No. 10 = 89 % Passing No. 40 =…

A:

Q: The moisture content of a soil sample is 0.24, its void ratio is 79%, and its specific gravity is…

A: Given data : Specific gravity (G)=2.63Moisture content (w)=0.24Void ratio (e)=79100=0.79

Q: A soil sample having a liquidity index of 0.79, a plasticity index of 15 and a plastic limit of 13.…

A: solution  we know Ip=15(plasticity index)plastic limit wp=13we know  Ip = wL-wp15 = wL-13wL=28

Q: A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic…

A: we have Liquid limit =30% Plastic limit =12%   U.S. Sieve Size                  Percentage Passing…

Q: For a soil sample in a natural condition, void ratio (e) is 0.67, degree of saturation (S) is 75%,…

A: Given data, Void ratio (e) = 0.67 S= 75% Gs= 2.7

Q: A liquid limit test performed on a soil sample has the following results, compute for the value of…

A:

Q: 22. For a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10…

A:

Q: The liquid limit (LL) of a soil has been found as 78% and the plastic limit ( PL ) as 37% .…

A: Given data: liquid limit (LL) = 78% plastic limit ( PL ) = 37%  water content (W) = 56 %

Q: I need the answer as soon as possible

A:

Q: A soil sample is oven-dried from its liquid limit state to its dry state causing a volume change of…

A:

Q: The void ratio of a soil sample is 0.79, its moisture content is 26%, and its specific gravity is…

A: Given Data Void ratio, e = 0.79Moisture content, w =26% =0.26Specific gravity, G = 2.73To find :…

Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…

A:

Q: The results of a standard Proctor test are given in the following table. Given: Mold volume : 1/30…

A:

Q: 4. Phase Diagram A soil sample was obtained at the underground parking garage that Dr. Barry is…

A: Given Data  Total volume of soil (VT) = 0.05 ft3  Total weight of soil (WT) = 4.2 lbs  Weight of…

Q: A Liquid Limit test was carried out on a sample of Clay with the following results: Number of taps…

A:

Q: A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…

A:

Q: Determine moisture content

A: Given data : Specific gravity (GS)=2.6Weight of soil sample (w1)=0.7 kgWeight after oven drying…

Q: If the water content of a fully, saturated soil mass is 100%, then the voids ratio of the sample is…

A:

Q: Mechanical analysis on four different samples designated as A, B, Cand Dwere carried out in a soil…

A:

Q: 4. A soil sample having a liquidity index of 0.85, a plasticity index of 16.50 and a plastic limit…

A:

Q: Mechanical analysis on four different samples designated as A, B. Cand D were carried out in a soil…

A:

Q: Given the test results that follow, classify the soil in both the Unified Soil Classification System…

A: Given:- The test result of the soil sample is given  The percent passing through No. 4 sieve = 48…

Q: Mechanical analysis on four different samples designated as A, B. Cand D were carried out in a soil…

A:

Q: The soil sample with soil profile shown below is in a container with constant cross-sectional area…

A: given- Area of cross section of container having soil-A=4550 mm2Total height H=600 mmSpecific…

Fluid Materials

In general terms, anything that flows can be termed as a fluid. In other words, a fluid is any substance that cannot resist shear forces and deforms continuously under the application of external shear forces. Fluid materials differ completely from solid materials such as metals and alloys. For instance, if we consider two infinitesimally small cross-sectional areas of fluid materials and solid materials, and apply shear forces to these elements, both the elements will undergo deformation. Upon releasing the shear force, the element of the solid materials will regain its original orientation, but the element of the fluid materials will keep on deforming continuously under the action of the shear force.