a. Calculate A, G* for the following reaction at 298 K. CIO3(aq) + 5 Cl¯(aq) + 6 H+ (aq) → 3 Cl₂(g) +3 H₂O(l) Use the data provided below. 2 C1O3(aq) + 12 H+ (aq) + 10 e¯ → Cl₂ (g) + 6 H₂O(l), E = 1.47 V Cl₂ (g) + 2 e E = 1.36 V A₂G* = → 2 Cl¯ (aq), kj b. Calculate A, G* for the following reaction at 298 K. AgI(s)+Br (aq)→ AgBr(s)+I(aq) Use the data provided below. AgBr(s)+e +Ag(s)+Br (aq), E = 0.0713 V Agl(s) +e → Ag(8) + I¯ (aq), E = -0.15 V A, G = kj
a. Calculate A, G* for the following reaction at 298 K. CIO3(aq) + 5 Cl¯(aq) + 6 H+ (aq) → 3 Cl₂(g) +3 H₂O(l) Use the data provided below. 2 C1O3(aq) + 12 H+ (aq) + 10 e¯ → Cl₂ (g) + 6 H₂O(l), E = 1.47 V Cl₂ (g) + 2 e E = 1.36 V A₂G* = → 2 Cl¯ (aq), kj b. Calculate A, G* for the following reaction at 298 K. AgI(s)+Br (aq)→ AgBr(s)+I(aq) Use the data provided below. AgBr(s)+e +Ag(s)+Br (aq), E = 0.0713 V Agl(s) +e → Ag(8) + I¯ (aq), E = -0.15 V A, G = kj
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:a. Calculate AG for the following reaction at 298 K.
Use the data provided below.
2 ClO3¯(aq) + 12 H† (aq) + 10 e¯ → Cl₂ (g) + 6 H₂ O(l),
EⓇ
= 1.47 V
Cl₂(g) +2 e → 2 Cl¯ (aq),
= 1.36 V
E
CIO3(aq) + 5 CHI¯ (aq) + 6 H+ (aq) → 3 Clą (g) + 3 H₂O(l)
A, G =
kJ
b. Calculate A,G for the following reaction at 298 K.
AgI(s)+Br (aq) → AgBr(s)+I(aq)
Use the data provided below.
AgBr(s)+e +Ag(s)+Br (aq),
= 0.0713 V
AgI(s) + e¯ → Ag(s) + I¯ (aq),
E = -0.15 V
A, G
E
kJ
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