A. Answer as directed. 5 pts each. 1. Draw a molecule that contains sp, sp², and sp³ hybridized carbon atom. 2. Explain why 1,2-dichloroethyne is nonpolar while cis-1,2-dichloroethene is not. Provide illustrations to support your answer. B. Given the molecular formulae, provide the table with relevant details. Methylamine is already done for you.. Condensed Formula CH3NH2 (methylamine/ methanamine) Drawing and Hybridization Molecular Geometry Approximate Bond Angle(s) with Drawing Molecular Polarity H-N-H: <109.5° H-N-C: >109.5° CH3 sp³ (around N) H CF4 '\' (around C) The angle formu (around Carbon-3) 10SY Polar " CH3 H Condensed Formula Drawing and Molecular Geometry Hybridization Approximate Bond Angle(s) with Drawing (around the rightmost Carbon) 4 CH,CH₂SH (around S) 5 CHOOCH (dimethyl peroxide) (around left side O) 6 CH₁C=N (around middle C) 7 CH,COOH 8 CH3COOH (around Carbon-1) (around Carbon-2) Molecular Polarity

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter3: Electron Orbitals
Section: Chapter Questions
Problem 14CTQ
icon
Related questions
Question
A. Answer as directed. 5 pts each.
1. Draw a molecule that contains sp, sp², and sp³ hybridized carbon atom.
2. Explain why 1,2-dichloroethyne is nonpolar while cis-1,2-dichloroethene is not. Provide
illustrations to support your answer.
B. Given the molecular formulae, provide the table with relevant details.
Methylamine is already done for you..
Condensed
Formula
CH3NH2
(methylamine/
methanamine)
Drawing
and
Hybridization
Molecular
Geometry
Approximate
Bond Angle(s)
with Drawing
Molecular
Polarity
H-N-H: <109.5°
H-N-C: >109.5°
CH3
sp³
(around N)
H
CF4
'\'
(around C)
The angle formu
(around Carbon-3)
10SY
Polar
"
CH3
H
Condensed
Formula
Drawing
and
Molecular
Geometry
Hybridization
Approximate
Bond Angle(s)
with Drawing
(around the
rightmost Carbon)
4
CH,CH₂SH
(around S)
5
CHOOCH
(dimethyl peroxide)
(around left side O)
6
CH₁C=N
(around middle C)
7
CH,COOH
8
CH3COOH
(around Carbon-1)
(around Carbon-2)
Molecular
Polarity
Transcribed Image Text:A. Answer as directed. 5 pts each. 1. Draw a molecule that contains sp, sp², and sp³ hybridized carbon atom. 2. Explain why 1,2-dichloroethyne is nonpolar while cis-1,2-dichloroethene is not. Provide illustrations to support your answer. B. Given the molecular formulae, provide the table with relevant details. Methylamine is already done for you.. Condensed Formula CH3NH2 (methylamine/ methanamine) Drawing and Hybridization Molecular Geometry Approximate Bond Angle(s) with Drawing Molecular Polarity H-N-H: <109.5° H-N-C: >109.5° CH3 sp³ (around N) H CF4 '\' (around C) The angle formu (around Carbon-3) 10SY Polar " CH3 H Condensed Formula Drawing and Molecular Geometry Hybridization Approximate Bond Angle(s) with Drawing (around the rightmost Carbon) 4 CH,CH₂SH (around S) 5 CHOOCH (dimethyl peroxide) (around left side O) 6 CH₁C=N (around middle C) 7 CH,COOH 8 CH3COOH (around Carbon-1) (around Carbon-2) Molecular Polarity
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Organic Chemistry: A Guided Inquiry
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:
9780618974122
Author:
Andrei Straumanis
Publisher:
Cengage Learning