a. #5 Prove that for all integers n, it is the case that n is even if an only if 3n is even. That is, prove both implications: if n is even, then 3n is even, and if 3n is even, then n is even. b. #7 Consider the statement: for all integers a and b, if a is even and b is a multiple of 3, then ab is a multiple of 6.Then state the converse, tell if it is true, and prove or disprove.

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A: Topic: INTEGERS   The answer is given below:

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A: The proof is correct. More details on step 2 is attached. $\blacksquare$

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