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A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = 42 kN/m, LAB = 1.2 m, LBC = 2.4 m, and LCD = 1.2 m. Consider the entire 4.8 m length of the bear %3D and determine: (a) the maximum tensile bending stress at any location along the beam (enter a positive answer), and (b) the maximum compressive bending stress at any location along the beam (enter a negative answer). В LAB LBC LCD WT305 x 41 Answer: (а) Оmax,T 3 MPa (b) ơmaxC = MPa

A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = 42 kN/m, LAB = 1.2 m, LBC = 2.4 m, and LCD = 1.2 m. Consider the entire 4.8 m length of the bear %3D and determine: (a) the maximum tensile bending stress at any location along the beam (enter a positive answer), and (b) the maximum compressive bending stress at any location along the beam (enter a negative answer). В LAB LBC LCD WT305 x 41 Answer: (а) Оmax,T 3 MPa (b) ơmaxC = MPa

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = = 42 kN/m, LAB = 1.2 m, LBC = 2.4 m, and LCD = 1.2 m. Consider the entire 4.8 m length of the beam and determine: (a) the maximum tensile bending stress at any location along the beam (enter a positive answer), and (b) the maximum compressive bending stress at any location along the beam (enter a negative answer). A B LAB LBC LCD WT305 x 41 Answer: (a) Omax,T = MPа (b) Omax,C = MPa %3D
Transcribed Image Text:A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = = 42 kN/m, LAB = 1.2 m, LBC = 2.4 m, and LCD = 1.2 m. Consider the entire 4.8 m length of the beam and determine: (a) the maximum tensile bending stress at any location along the beam (enter a positive answer), and (b) the maximum compressive bending stress at any location along the beam (enter a negative answer). A B LAB LBC LCD WT305 x 41 Answer: (a) Omax,T = MPа (b) Omax,C = MPa %3D
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