Homework Help is Here – Start Your Trial Now!
Science
Chemistry
a) Would 1 gram of gold weigh more than 1 gram of aluminum? No. They are both one gram, so weigh the same. 1g gold would be more dense, but not weigh more. How would the volumes of these samples compare? The allinum has much more volume than the gold, because it is much less dense. b) If you had a 1 gram sample and a 10 gram sample of the same substance, how would you expect their volumes to compare? 1 gram would have much less volume than 10 grams. c) If you had 1 kg of silver, how much space would it take up? d) How many 100 g bars of copper would you need to fill a 1 L box? 1g=1/1000L 100g= 100/1000L = 10/100L = 0.1L So if 100g = 0.1L, and if 1L=1000g, then you would need to multiply both sides by 10, to make 1000g=1L, which means that you need 10 100g bars of copper to fill a 1L box.

a) Would 1 gram of gold weigh more than 1 gram of aluminum? No. They are both one gram, so weigh the same. 1g gold would be more dense, but not weigh more. How would the volumes of these samples compare? The allinum has much more volume than the gold, because it is much less dense. b) If you had a 1 gram sample and a 10 gram sample of the same substance, how would you expect their volumes to compare? 1 gram would have much less volume than 10 grams. c) If you had 1 kg of silver, how much space would it take up? d) How many 100 g bars of copper would you need to fill a 1 L box? 1g=1/1000L 100g= 100/1000L = 10/100L = 0.1L So if 100g = 0.1L, and if 1L=1000g, then you would need to multiply both sides by 10, to make 1000g=1L, which means that you need 10 100g bars of copper to fill a 1L box.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question

Please disregard all work, and give answers with in depth explanations. Thanks! 

Part 2: Problem Solving Using what you have learned about density so far, answer the following questions. Be sure to show all calculations, taking into account significant digits. Explain your reasoning thoroughly using complete sentences. 1. Use the table of density values below to answer the following questions. Accepted Density Values for Various Metals copper brass *** F Metal Density (g/mL) gold 19.3 lead 11.3 silver 10.5 9.0 8.4 iron 7.9 tin 7.3 zinc 7.1 c) If you had 1 kg of silver, how much space would it take up? d) How many 100 g bars of copper would you need to fill a 1 L box? 1g= 1/1000L 100g= 100/1000L = 10/100L = 0.1L aluminum 2.7 a) Would 1 gram of gold weigh more than 1 gram of aluminum? No. They are both one gram, so weigh the same. 1g gold would be more dense, but not weigh more. How would the volumes of these samples compare? The allinum has much more volume than the gold, because it is much less dense. b) If you had a 1 gram sample and a 10 gram sample of the same substance, how would you expect their volumes to compare? 1 gram would have much less volume than 10 grams. So if 100g =0.1L, and if 1L=1000g, then you would need to multiply both sides by 10, to make 1000g=1L, which means that you need 10 100g bars of copper to fill a 1L box.
Transcribed Image Text:Part 2: Problem Solving Using what you have learned about density so far, answer the following questions. Be sure to show all calculations, taking into account significant digits. Explain your reasoning thoroughly using complete sentences. 1. Use the table of density values below to answer the following questions. Accepted Density Values for Various Metals copper brass *** F Metal Density (g/mL) gold 19.3 lead 11.3 silver 10.5 9.0 8.4 iron 7.9 tin 7.3 zinc 7.1 c) If you had 1 kg of silver, how much space would it take up? d) How many 100 g bars of copper would you need to fill a 1 L box? 1g= 1/1000L 100g= 100/1000L = 10/100L = 0.1L aluminum 2.7 a) Would 1 gram of gold weigh more than 1 gram of aluminum? No. They are both one gram, so weigh the same. 1g gold would be more dense, but not weigh more. How would the volumes of these samples compare? The allinum has much more volume than the gold, because it is much less dense. b) If you had a 1 gram sample and a 10 gram sample of the same substance, how would you expect their volumes to compare? 1 gram would have much less volume than 10 grams. So if 100g =0.1L, and if 1L=1000g, then you would need to multiply both sides by 10, to make 1000g=1L, which means that you need 10 100g bars of copper to fill a 1L box.
2. Use the table below to answer the following questions. Substance A B C Mass (g) 90.0 Substance 65.0 Donnelyon 40.5 Machacium Volume (mL) Density of Water = 1.00 g/mL a) Which substance(s) will float in water? Explain. Lurainogen 30.0 C, c is the only substance that is less dense than water, so it is the only substance that will float in water. 50.5 b) If you had 1 kg of each substance, which one would take up the most volume? Explain. If I had 1kg of each, substance A takes up the most. This is because it is the most dense. c) If you had 1 L of each substance, which one would have the most mass? Explain. The same, A takes up the most, because it is the most dense. 45.1 3. A small elevator with a volume of 100 L has a maximum weight capacity of 500 kg. If you had a 500 kg sample of each of the following rare and precious substances, which one(s) could you fit in the elevator? Explain using calculations and words. D: 1.37 kg/L 1.37x500=685kg 1Lx500=500L 685kg/500L. Nope, D can't fit. M: 5.9 kg/L 5.9x500 29250 Density 13.7 kg/L 5.9 kg/L 3.8 kg/L
Transcribed Image Text:2. Use the table below to answer the following questions. Substance A B C Mass (g) 90.0 Substance 65.0 Donnelyon 40.5 Machacium Volume (mL) Density of Water = 1.00 g/mL a) Which substance(s) will float in water? Explain. Lurainogen 30.0 C, c is the only substance that is less dense than water, so it is the only substance that will float in water. 50.5 b) If you had 1 kg of each substance, which one would take up the most volume? Explain. If I had 1kg of each, substance A takes up the most. This is because it is the most dense. c) If you had 1 L of each substance, which one would have the most mass? Explain. The same, A takes up the most, because it is the most dense. 45.1 3. A small elevator with a volume of 100 L has a maximum weight capacity of 500 kg. If you had a 500 kg sample of each of the following rare and precious substances, which one(s) could you fit in the elevator? Explain using calculations and words. D: 1.37 kg/L 1.37x500=685kg 1Lx500=500L 685kg/500L. Nope, D can't fit. M: 5.9 kg/L 5.9x500 29250 Density 13.7 kg/L 5.9 kg/L 3.8 kg/L
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 5 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Matter
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS