A wooden block is at rest on a frictionless horizontal plane, connected to a rod of negligible mass and length l. The rod is attached to the horizontal plane at its other end and can rotate around its attachment point. A lead tree of mass m = 0.5 M and velocity v, moving parallel to the horizontal plane and perpendicular to the solid bar, strikes the block and becomes embedded in the block. Taking into account the angular momentum of the lead+block system, find how much of the kinetic energy lost in the collision corresponds to a fraction of the kinetic energy before the collision.
A wooden block is at rest on a frictionless horizontal plane, connected to a rod of negligible mass and length l. The rod is attached to the horizontal plane at its other end and can rotate around its attachment point. A lead tree of mass m = 0.5 M and velocity v, moving parallel to the horizontal plane and perpendicular to the solid bar, strikes the block and becomes embedded in the block. Taking into account the angular momentum of the lead+block system, find how much of the kinetic energy lost in the collision corresponds to a fraction of the kinetic energy before the collision.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A wooden block is at rest on a frictionless horizontal plane, connected to a rod of negligible mass and length l. The rod is attached to the horizontal plane at its other end and can rotate around its attachment point. A lead tree of mass m = 0.5 M and velocity v, moving parallel to the horizontal plane and perpendicular to the solid bar, strikes the block and becomes embedded in the block. Taking into account the
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