A window-mounted air conditioner removes 4.3 kJ from the inside of a home using 1.75 kJ work input. How much heat is released outside?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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### Problem Statement

A window-mounted air conditioner removes 4.3 kJ from the inside of a home using 1.75 kJ work input. How much heat is released outside?

[Input Box] 

### Explanation

This text presents a thermodynamic problem related to air conditioning systems. The task involves calculating the amount of heat expelled outside based on the given heat removal and work input. This is a typical application of the first law of thermodynamics, which can be represented by the equation:

\[ Q_{\text{out}} = Q_{\text{in}} + W \]

Where:
- \( Q_{\text{out}} \) is the heat released outside.
- \( Q_{\text{in}} \) is the heat removed from inside, which is 4.3 kJ.
- \( W \) is the work input, which is 1.75 kJ.

By adding the heat removed and the work input, you can find the heat released outside.
Transcribed Image Text:### Problem Statement A window-mounted air conditioner removes 4.3 kJ from the inside of a home using 1.75 kJ work input. How much heat is released outside? [Input Box] ### Explanation This text presents a thermodynamic problem related to air conditioning systems. The task involves calculating the amount of heat expelled outside based on the given heat removal and work input. This is a typical application of the first law of thermodynamics, which can be represented by the equation: \[ Q_{\text{out}} = Q_{\text{in}} + W \] Where: - \( Q_{\text{out}} \) is the heat released outside. - \( Q_{\text{in}} \) is the heat removed from inside, which is 4.3 kJ. - \( W \) is the work input, which is 1.75 kJ. By adding the heat removed and the work input, you can find the heat released outside.
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