A wide, shallow sand-bed channel has a slope of 0.00105 (assume smooth channel banks). The average grain size = 0.36 mm at isb = 40.2%. The flow depth of the channel is equal to 3.3 ft at flowrate and cross area of 5380 ft^3/s and 640 ft^2, respectively. Based on Einstein (1950) for total bed-load material transport model using size fraction, Find the following by choosing the correct answer of the following:

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A wide, shallow sand-bed channel has
a slope of
0.00105 (assume smooth channel banks).
The average grain size = 0.36
mm at isb = 40.2%. The flow depth of the
channel is equal to 3.3
ft at flowrate and cross area of 5380 ft^3/s
and 640 ft^2,
respectively. Based on Einstein (1950) for
total bed-load material transport model
using size fraction, Find the following by
choosing the correct answer of the
following:
7- If the settling velocity Vss = 4.5
cm/s and u*'= 0.323 fps, the Rouse
Exponent is equal to:
1.14
0.85
0.57
0.35
8- The integrals 11 and 12 based on
Einstein (1950) suspended-load
transport equation is equal to:
19.0, -40
1.8, -6.5
4.5, -2.4
3.0, -1
*
Transcribed Image Text:A wide, shallow sand-bed channel has a slope of 0.00105 (assume smooth channel banks). The average grain size = 0.36 mm at isb = 40.2%. The flow depth of the channel is equal to 3.3 ft at flowrate and cross area of 5380 ft^3/s and 640 ft^2, respectively. Based on Einstein (1950) for total bed-load material transport model using size fraction, Find the following by choosing the correct answer of the following: 7- If the settling velocity Vss = 4.5 cm/s and u*'= 0.323 fps, the Rouse Exponent is equal to: 1.14 0.85 0.57 0.35 8- The integrals 11 and 12 based on Einstein (1950) suspended-load transport equation is equal to: 19.0, -40 1.8, -6.5 4.5, -2.4 3.0, -1 *
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