(a) What is the power loss due to resistance in the line? MW
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- How at maximum power output is the terminal voltage of the battery half its EMF?A voltage Δ V n resistors, each of resistance R. The circuit components are reconnected in a parallel configuration, and voltage Δ V is again applied. Show that the power consumed by the series configuration is 1/ n2 times the power consumed by the parallel configuration.(a) In the figure what value must R have if the current in the circuit is to be 1.1 mA? Take ε1 = 3.0 V, ε2 = 4.2 V, and r1 = r2 = 2.7 Ω. (b) What is the rate at which thermal energy appears in R?
- In the circuit shown the capacitor starts discharged. The switch S is closed to theupper position at t = 0.(a) What is the voltage in the capacitor at t = 2 seconds?(b) How much time does it take the capacitor to reach 99% of its maximum voltage.A 215-KV power transmission line carrying 500 A is hung from grounded metal towers by ceramic insulators, each having a 1.10 x 10 resistance. (a) What is the resistance to ground of 50 of these insulators? (Assume the insulators are connected in parallel.) 2.267 Q (b) Calculate the power dissipated by 50 of them. X What is the voltage across the effective resistance? How can you find the power from the voltage and the resistance? W (c) What fraction of the power carried by the line is this? P x Protal What is the total power carried by the line?You take a 6.34 V battery, a 226 kQ resistor, and an uncharged capacitor to put together a series circuit. You connect the battery and after 21.2 seconds the current in the circuit has fallen to 61% of its initial value. What is the value of the capacitor in microfarads (µF)? (Enter answer as an integer. Do not enter unit.) A Click Submit to complete this assessment. «< Question 2 of 2