a) What is the physical interpretation of the wave function in the Schrodinger Equation? b) The physical interpretation of the wavefunction and the fact that it is a solution of the Schroedinger equaton, which is a 2nd order differential equation, causes many restrictions on an acceptable wave function solution: (i) it must be single valued; (ii) it must be continuous; (iii) its slope must be continuous; and (iv) it must be normalizable or normalized. Sketch the following functions and check whether they can be wave function. Explain your answers.
a) What is the physical interpretation of the wave function in the Schrodinger Equation?
b) The physical interpretation of the wavefunction and the fact that it is a solution of the Schroedinger equaton, which is a 2nd order differential equation, causes many restrictions on an acceptable wave function solution: (i) it must be single valued; (ii) it must be continuous; (iii) its slope must be continuous; and (iv) it must be normalizable or normalized. Sketch the following functions and check whether they can be wave function. Explain your answers.
1) Ψ(x)=1/(1+x), for 0 ≤ x ≤ ∞
2) Ψ(x) = |sin(π*x)|, for 0 ≤ x ≤ 2
3) Ψ(x)=ln(x), for 1 ≤ x ≤ ∞
4) Ψ(x)=0, for −1 ≤ x < 0
5) Ψ(x)=1, for 0 ≤ x < 1
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