(a) What is the electric fields E in the wire! (b) What is the current in the wire? (c) Using the Ohms law, what is the wire resistances R? (d) Find the resistivity, p, of the wire. (e) Using this resistivity calculate the wire resistances R again.

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Chapter1: Units, Trigonometry. And Vectors
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If there a way to find L2 and A2? For this problem? If so can you explain it please.
(a) What is the electric fields E in the wire!
(b) What is the current in the wire?
(c) Using the Ohms law, what is the wire resistances R?
(d) Find the resistivity, p, of the wire.
(e) Using this resistivity calculate the wire resistances R again.
Transcribed Image Text:(a) What is the electric fields E in the wire! (b) What is the current in the wire? (c) Using the Ohms law, what is the wire resistances R? (d) Find the resistivity, p, of the wire. (e) Using this resistivity calculate the wire resistances R again.
Expert Solution
Step 1

Given data:

The electron density is: n=6×1028 electrons/m3=6×1028×1.6×10-19/m3

The drift speed of the electron is: u=7×10-5 m/s

The length of wire is: L=1.4 m

The area of the wire is: A=9×10-8 m2

The drift voltage is: V=12 v

The current through the wire is: I

The electric field in the wire is: E

The resistance is: R

The resistivity of the wire is: ρ

(a)The electric field in the wire is calculated as,

E=VL=12 v1.4 m=8.57 v/m

Thus, the electric field in the wire is 8.57 v/m.

(b)The current in the wire is calculated as,

I=nAu=6×1028×1.6×10-19 C/m3×9×10-8 m2×7×10-5 m/s=0.06 A

Thus, the current in the wire is 0.06 A.

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