**Astronomical Data****Table D1 Astronomical Data**---### Celestial Object Characteristics| **Celestial Object** | **Mean Distance from Sun (million km)** | **Period of Revolution (d = days) (y = years)** | **Period of Rotation at Equator** | **Eccentricity of Orbit** ||----------------------|-----------------------------------------|---------------------------------------------|----------------------------------|--------------------------|| Sun | – | – | 27 d | – || Mercury | 57.9 | 88 d | 59 d | 0.206 || Venus | 108.2 | 224.7 d | 243 d | 0.007 || Earth | 149.6 | 365.26 d | 23 h 56 min 4 s | 0.017 || Mars | 227.9 | 687 d | 24 h 37 min 23 s | 0.093 || Jupiter | 778.4 | 11.9 y | 9 h 50 min 30 s | 0.048 || Saturn | 1426.7 | 29.5 y | 10 h 14 min | 0.054 || Uranus | 2871.0 | 84.0 y | 17 h 14 min | 0.047 || Neptune | 4498.3 | 164.8 y | 16 h | 0.009 || Earth’s Moon | 149.6 (0.386 from Earth) | 27.3 d | 27.3 d | 0.055 |### Additional Data| **Celestial Object** | **Equatorial Diameter (km)** | **Mass (Earth = 1)** | **Density (g/cm³)** ||----------------------|------------------------------|----------------------|----------------------|| Sun | 1,392,000 | 333,000.00 | 1.4 || Mercury | 4879 | 0.06 | 5.4 || Venus | 12,104 | ### Gravitational Forces on Triton and Earth#### (a) Calculating the Difference in Forces on Triton**Question:** What is the difference between the forces due to Neptune on a 1.0 kg mass located at the near side of Triton and at the far side of Triton? Triton has a mean radius of 1,353 km and a mean orbital radius about Neptune of 354,800 km. (Enter the magnitude in newtons.)**Answer:** \[ \Delta F_{\text{Triton due to Neptune}} = \] [Input Box] N#### (b) Comparing Tidal Forces to Earth**Compare this difference to the difference for Earth due to the Moon, 0.22 × 10⁻⁵ N.** (Tidal forces are the cause of volcanic activity on some moons.)**Ratio Calculation:** \[ \frac{\Delta F_{\text{Triton due to Neptune}}}{\Delta F_{\text{Earth due to Moon}}} = \] [Input Box]This exercise involves calculating the gravitational force differences and comparing them to understand tidal influences, which can lead to phenomena such as volcanic activity on moons.

Mass of Earth ME=5.97×1024 kg The mass of Neptune MN=17.15 MEMN=17.155.97×1024kg=102.38×1024 kg…

(a) What is the difference between the forces due to Neptune on a 1.0 kg mass located at the near side of Triton and at the far side of Triton? Triton has a mean radius of 1,353 km and a mean orbital radius about Neptune of 354,800 km. (Enter the magnitude in newtons.) (b) Compare this difference to the difference for Earth due to the Moon, 0.22 x 10-5 N. (Tidal forces are the cause of volcanic activity on some moons.) AFTriton due to Neptune AFEarth due to Moon

(a) What is the difference between the forces due to Neptune on a 1.0 kg mass located at the near side of Triton and at the far side of Triton? Triton has a mean radius of 1,353 km and a mean orbital radius about Neptune of 354,800 km. (Enter the magnitude in newtons.) (b) Compare this difference to the difference for Earth due to the Moon, 0.22 x 10-5 N. (Tidal forces are the cause of volcanic activity on some moons.) AFTriton due to Neptune AFEarth due to Moon

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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