There is one part to this question. I need to know the km/s. Thank you! **Problem Statement:**What is the escape velocity from the surface of Rhea if its mass is \(2.3 \times 10^{21}\) kg and its radius is \(7.7 \times 10^{2}\) km? *Hint: Use the formula for escape velocity, \(V_e = \sqrt{\frac{2GM}{r}}\)***Answer Field:**\[ \_\_\_\_\_\_ \text{ km/s} \]**Explanation:**To solve this problem, you will need to use the escape velocity formula:\[ V_e = \sqrt{\frac{2GM}{r}} \]where:- \( G \) is the gravitational constant (\(6.674 \times 10^{-11} \, \text{m}^3\, \text{kg}^{-1}\, \text{s}^{-2}\)),- \( M \) is the mass of the body (in this case, Rhea, which is given as \(2.3 \times 10^{21}\) kg),- \( r \) is the radius of the body (Rhea's radius is \(7.7 \times 10^{2}\) km, which should be converted to meters for the calculation).To compute the escape velocity, substitute the given values into the formula, remembering to convert the radius into meters:\[ r = 7.7 \times 10^2 \text{ km} = 7.7 \times 10^5 \text{ m} \]Plug these into the formula to find \( V_e \).

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2GM What is the escape velocity from the surface of Rhea if its mass is 2.3 x 1021 kg and its radius is 7.7 × 102 km? (Hint: Use the formula for escape velocity, V. = V km/s