(a) What is the current in each of the resistors? I = A I2 = A I3 = |A (b) How much power is delivered to each of the resistors? P1 |w P2 P3
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- In the circuit shown below, R1=10 N, R2=32 Q. Ω. Find the equivalent resistance of this circuit: Reg = A. Find the current passing through the R1 resistor: I1= A. Find the current passing through the 5-2 resistor: 15= W. Find the power dissipated on the 5-0 resistor: P5= 10 Q 50 60 V + 10 Q R2 R1 R2When different resistors are connected in parallel across an ideal battery, we can be certain that a the same current flows in each one. b the potential difference across each is the same. c the power dissipated in each is the same. d their equivalent resistance is greater than the resistance of any one of the individual resistances. e their equivalent resistance is equal to the average of the individual resistances.Listen In the following circuit, V₁ =107 V and V2 = 126 V and all the resistors are R = 19 Q Find the current that passes through R2 R₁ ww R₂ ww ww Your Answer: R3 V₂
- (a) What is the terminal voltage (in V) of a large 1.90 V carbon-zinc dry cell used in a physics lab to supply 1.20 A to a circuit, if the cell's internal resistance is 0.200 Q? V (b) How much electrical power (in W) does the cell produce? W (c) What power (in W) goes to its load? WTwo copper wires have the same volume, but wire 2 is 25 % longer than wire 1. The ratio of the resistances of the two wires R2/R1 is ( Hint: radius will not be same) 0.82 0.91 1.2 1.56 1.0F₁ = L1, B₂ чт вът Різі чом =1032 V R -Gv 100 qüdrh I 1 R2 R23 2. Four resistors and a 6.0-V battery are arranged as shown in the circuit diagram. Find the equivalent resistance of the circuit b. Find the current through the 10-Ohm resistor a. sonsufit c. Find the power delivered to the 10-Ohm resistor R₁-4092 -18V -18V 13 C+ D B=6V 6VI Azov I=I1 + 0.64 AQUOS to 218-12 = 30 I H = -1 R4-2002 14. 0.64 1₂V R₂-3002 -IA F 12V E R3=1092 holong s vivang to 6 DS sailwaqogani THOS T20 3. A horizontal wire of length 6.0m carries a current of 6.0A and is oriented so that Forth's magnetic field is due north at this