a) What is the concentration of a solution prepared by mixing 35.0 mL of o.10 Macetic acid with 15.0 mL of water? b) Calculate [H;O*], [C:H;Oz¯ ], and [HC2H;O2] in this solution. c) What is the pH of this solution?
Parts A-C (These are NOT graded, this is prep work to learn do a lab assignment so I can do the actual lab correctly)
![1.
a) What is the concentration of a solution prepared by mixing 35.0 mL of o.10 Macetic acid with 15.0 mL
of water?
b) Calculate [H;Oʻ], [CH;O2 ], and [HC2H;O2] in this solution.
c) What is the pH of this solution?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85a2fef8-75c6-4f70-afce-e76c8de2cc0b%2F8f2ea403-2bf4-45d9-bfcb-e8993692830e%2Fbnatv5q_processed.png&w=3840&q=75)
a) Given : Concentration of acetic acid i.e HC2H3O2 taken = 0.10 M
Volume of HC2H3O2 solution taken = 35 mL
And volume of water added = 15 mL
=> Volume of final solution = volume of initial HC2H3O2 solution + volume of water added = 35 + 15 = 50 mL
Since only water is being added in the solution. Hence moles of HC2H3O2 present will be same in initial and final solution.
=> Moles of HC2H3O2 in initial solution = moles of HC2H3O2 in final solution
Since moles = concentration X volume of solution
=> Concentration of initial solution X volume of initial solution = concentration of final solution X volume of final solution
=> 0.10 X 35 = concentration of final solution X 50
=> concentration of final HC2H3O2 solution = 0.07 M
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