A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 400 people, 84% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 90% at the 0.10 significance level. The null and alternative hypothesis would be: Ho :p=0.9 Ho:p>0.9 Ho:- > 0.9 H₁p0.9 H₁: p < 0.9 H₁ μ< 0.9 O The test is: two-tailed left-tailed right-tailed o The test statistic is: The p-value is: Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Ho : |=0.9 H : p< 0.9 Ho:}<0.9 ở H₁0.9 H₁ p > 0.9 H₁ μ> 0.9 O (to 3 decimals) (to 4 decimals)

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A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting
their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in
a sample of 400 people, 84% of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is smaller than 90% at the 0.10 significance
level.
The null and alternative hypothesis would be:
Ho: p= 0.9 Hop≥ 0.9 Hopμ ≥ 0.9 H₁ μ = 0.9 Ho: p ≤ 0.9 Ho: ≤ 0.9 0
H₁: p0.9 H₁: p < 0.9 H₁ μ< 0.9 H₁ μ0.9 H₁: p > 0.9 H₁: >0.9
The test is:
two-tailed left-tailed right-tailed o
The test statistic is:
The p-value is:
Based on this we:
Reject the null hypothesis
O Fail to reject the null hypothesis
(to 3 decimals)
(to 4 decimals)
Transcribed Image Text:A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 400 people, 84% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 90% at the 0.10 significance level. The null and alternative hypothesis would be: Ho: p= 0.9 Hop≥ 0.9 Hopμ ≥ 0.9 H₁ μ = 0.9 Ho: p ≤ 0.9 Ho: ≤ 0.9 0 H₁: p0.9 H₁: p < 0.9 H₁ μ< 0.9 H₁ μ0.9 H₁: p > 0.9 H₁: >0.9 The test is: two-tailed left-tailed right-tailed o The test statistic is: The p-value is: Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis (to 3 decimals) (to 4 decimals)
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