A well is installed in a unconfined aquifer. Determine the drawdown (ft) at the well if: the radius of influence = 500 ft. The thickness of unconfined aquifer = 95 ft The well diameter =9 in Pump rate =250 gal/min. Hydraulic conductivity = 0.001 ft/sec.

A well is installed in a unconfined aquifer. Determine the drawdown (ft) at the well if: the radius of influence = 500 ft. The thickness of unconfined aquifer = 95 ft The well diameter =9 in Pump rate =250 gal/min. Hydraulic conductivity = 0.001 ft/sec.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: In an aquifer of 50m thickness ,a 20 cm diameter well is pumped at a uniform rate of o.o5m3 /sec .if…

A: To determine: Hydraulic Conductivity of aquifer Radius of influence Drawdown of well

Q: If oil has kinematic viscosity 4 x 105 m2/s, and specific gravity is 0.9, flows from the upper to…

Q: A reservoir is shown in Figure E4.6a. (a) Draw the flownet. (b) Calculate the flow rate. (c) How…

A: Solution: Given Data k=1×10-9 ft/s

Q: a 45-cm well in an unconfined aquifer of saturated thickness of 48 m yields 701 lpm (liters per…

Q: A 400 mm diameter well fully penetrates a confined aquifer of thickness 20 m is pumped at a constant…

A: Solution:

Q: A well is installed in a unconfined aquifer. Determine the drawdown (ft) at the well if: the radius…

A: R=500ft H=95ft

Q: 4- A 1500 ft deep umping well has a 2.5 inch OD tubing inside a 8 in ID casing. Without the packer,…

A: Solution: Given: permeability k = 40 ms thickness h = 5 ft Porosity ϕ= 30v compressibility ct=…

Q: Estimate the transmissivity of confined - aquifer in steady state flow if you know the drawdown is 3…

A: S1=5m S2=3m rw=2m r2=30m

Q: 0cm diameter well fully penetrates an unconfined aquifer with saturate thickness ho-60m and…

A: GIVEN DATA:-⇒Diameter of well dw= 30 cm⇒radius of well rw= 302⇒rw=15 cm⇒Thickness ho= 60m⇒ro= 120…

Q: - A 20cm diameter well penetrates fully a confined aquifer of thickness 25m .when the well is pumped…

A: Given above data we have to find hydraulic conductivity, the radius of influence and drawdown

Q: A well with diameter of 42cm fully penetrates 32m below the static water table. After 24 hours of…

A: Given,Radius of well, rw = 0.422 = 0.21 mDischarge, Q = 6 m3/min = 660 m3/sec = 0.1 m3/secAt rw =…

Q: Question- Well Hydraulics Civil Engg. A 20cm well penetrated directly into a confined aquifer of…

A: Well penetrated into a confined aquifer- 20 cm well,Radius of well, rw=20/2=10…

Q: ) Calculate the discharge from a tubewell of 20-cm diameter penetrating fully into a confined…

A: Given data in question Diameter of well 20 cm Thickness 20 m Permeability 40 m/day Drawdowns 3m and…

Q: An unconfined aquifer has a thickness of 30m . A fully penetrating 20cm diameter well in this…

A: Given: The thickness of the aquifer is 30 m. The diameter of the well is 20 cm. The pumped rate of…

Q: Question- Three tube wells of 25 cm, diameter each are located at the three vertices of an…

A: Given data Diameter of well = 25 cm Spacing of well = 100 m Thickness of confined aquifer = 25 m…

Q: A 30 cm diameter well completely 15 points penetrates a confined aquifer of permeability of 45…

A: Consider the given figure

Q: 3. A permeameter is filled with sand. When water is allowed to flow through the device, a flow rate…

A: The given data is: Qwater=10 cm3/s ρoil=0.9 ρwaterμoil=1.8 μwater

Q: The wells shown below are in a leaky confined aquifer. The aquifer has a hydraulic conductivity of…

A: Data given k = 30 ft/d S = 0.0008 b = 45 ft b' = 8 ft k' = 0.45 ft/d QA = 150 gpm = 28 875 ft3/day…

Q: Example 5.23 Two 30 cm wells completely penetrate an artesian aquifer of thickness 15 m and are…

Q: A well is constructed to pump water from a confined aquifer. Two observation wells are constructed…

Q: b) Figure Q2 (b) shows the water piping system from reservoir A to reservoir B. The water level for…

Q: A town is planning to develop a new water supply from an aquifer. Two observation wells installed…

A: Calculation of total ground water discharge/ volumetric flow rate:

Q: An unconfined aquifer with a well pumping 0.4m³/s and saturated thickness is 24m.lf the drawdown 50m…

Q: A single ideal pumping well, with radius of 1.0 ft and flow rate of 155 gpm, exists in an ideal…

A: Given:- Confined aquifer The radius of pump rw= 1 ft Flow rate q= 155 gpm Thickness D= 82 ft Sw= 42…

Q: Q2) A fully penetrating well of diameter 0.3 m is located in an uncontined aquifer of saturated…

A: We have to compute the hydraulic conductivity

Q: A 10-in. diameter well is drilled to the bottom of an unconfined aquifer. The water table is…

A: Generally, pumping through a confined aquifer is computed by Dupits theory. The drawdown in the well…

Q: A conduit is carrying oil ( S = 0.75 ) and its absolute viscosity is 0.25 kg / m-s. If the flow rate…

A: Given- S=0.75μ=0.25Kg/m-sQ=0.45 cu.m/s

Q: QI. s) Q1: A 1 m diameter well penetrates vertically through a confined aquifer (30 m) thick. When…

Q: A 30 cm well penetrates 30 m below static water level. After a long period of pumping at a rate of…

A: The given data is: Diameter of well, d=30 cm=0.3 m H=30 m Q=1800 l/min=1800/(60*103)=0.03 m3/s…

Q: I need right solution with clear calculations. If you don't know the solution please leave it but…

A: Given : Diameter of well = 100 mm Thickness of confined aquifer = 11 m Permeability = 64.8 m/day…

Q: Q1: A 30cm diameter well penetrates vertically through an aquifer to an impermeable stratum located…

A: So = drawdown of test well dw = dia. of test well = 30 cm Q = pumping rest of test well = 1.2…

Concept explainers

Field applications of hydraulic conductivity

Hydraulic conductivity is one of the hydraulic properties of soil defined as a measurement of the ability of a porous medium to permit water movement or fluid flow through it. It is denoted by the letter K. It is influenced by the density and viscosity of the fluid. It is also called permeability. Hydraulic conductivity is defined as the ratio of velocity to the hydraulic gradient. The different methods used to determine the hydraulic conductivity are laboratory methods (constant head permeability tests and falling head tests), in-situ field methods (pumping in and pumping out tests), small scale field tests (infiltration tests and slug tests), and indirect methods such as estimation from grain size, consolidation test data, and horizontal capillary test. The pedotransfer function (PTF) method is a specific empirical estimating approach employed in the soil sciences is also used to determine the hydraulic conductivity of the soil.

Question

A well is installed in a unconfined aquifer. Determine the drawdown (ft) at the well if:
the radius of influence = 500 ft.
The thickness of unconfined aquifer = 95 ft
The well diameter =9 in
Pump rate =250 gal/min.
Hydraulic conductivity = 0.001 ft/sec.
44
2
33
11
25

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Field Applications of Hydraulic Conductivity

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Read the question carefully and give me right solution according to the question. Note: I want 100% right solution Thank you
Please aid me with this, i will also need to learn how to do this.
Please teach me.
A well is installed in a unconfined aquifer. Determine the drawdown (ft) at the well if: the radius of influence = 500 ft. The thickness of unconfined aquifer = 95 ft The well diameter =9 in Pump rate =250 gal/min. Hydraulic conductivity = 0.001 ft/sec. 44 7 O 33 11 25
Plz answer ASAP
B- A 20cm diameter well penetrates fully a confined aquifer of thickness 25m .when the well is pumped at a rate of 200 liters/ minute the drawdown in two observaƟons wells located at 10m and 100m distance from center of well are found to be 3.5m and 0.05 m respectively .calculate the hydraulic conductivity of the aquifer and the radius of influence and the drawdown in the well.?
A 12 inch diameter well was installed in an unconfined aquifer consisting of a 60 foot thick layer of sand. The water table was 15 feet below the ground surface before pumping of the well began. The well was then pumped at a rate of 30 gallons per minute and the water level in the well dropped to 45 feet below the ground surface after a steady-state condition was reached. The radius of well influence is 4000 feet. a) Calculate the permeability of the sand b) Compute and plot the drawdown surface
I need the answer as soon as possible
(I want the solution is necessary)
(b) Calculate the discharge from a tubewell of 20-cm diameter penetrating fully into a confined aquifer of 20-m thick and having a permeability of 40 m/day. The drawdown in the well is 3 m and zero drawdown at 300 m from the well. If the diameter of the well is doubled, find the percentage increase in the yield, the other conditions remaining the same. State the assumptions in the formula you use. Ans: (1303.7 lpm)
Question Two An unconfined aquifer with a well pumping 0.4m3/s and saturated thickness is 24m.lf the drawdown 50m from the well is 1m and the drawdown 100m from the well is 0.5m, calculate the hydraulic conductivity and transmissivity of the aquifer.The solution should include a labeled diagram.
I need right solution with clear calculations. If you don't know the solution please leave it but don't give me wrong solution. A 100 mm diameter well is drilled to withdraw water from a 11 m thick confined aquifer having coefficient of permeability equal to 64.8 m/d. The depth of water below the piezometric level is 30 m and it falls 2 m in the well while pumping. Calculate the discharge from the well when the radius of the circle of influence is 50 m.