A welder has just welded two pieces of carbon steel together and needs to quench the weld in a water bath down to room temperature (68°F). What is the minimum volume (gal) of water necessary to cool the 400°F weld down to thermal equilibrium?Remember: Convert °F to °CConversions:(°F - 32) x 5/9 = °C 1 gal = 3.78541 L1 lb = 0.453592 kg Additional Knowns:Cp water = 4184 J/kg°Cmsteel = 2 lbsTinitial water = 50°FCp steel= 620 J/kg°C Complete the following:List the unknown quantities? What equations are necessary to solve for the unknowns? How many gallons of water will it take?

When two substances are in physical contact with each other the heat is exchanged from one substance…

Answered: A welder has just welded two pieces of…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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A welder has just welded two pieces of carbon steel together and needs to quench the weld in a water bath down to room temperature (68°F). What is the minimum volume (gal) of water necessary to cool the 400°F weld down to thermal equilibrium?

Remember: Convert °F to °C

Conversions:
(°F - 32) x ⁵/₉ = °C	1 gal = 3.78541 L	1 lb = 0.453592 kg

Additional Knowns:
Cp _water = 4184 J/kg°C	m_steel = 2 lbs	T_{initial water}= 50°F
Cp _steel= 620 J/kg°C

Complete the following:

List the unknown quantities?
What equations are necessary to solve for the unknowns?
How many gallons of water will it take?

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