A weight scale using water can be devised using our knowledge of buoyancy. Consider the simple diagram of : buoyed block on pure water below: The Engineering ToolBax If you place an object on top of the block, it'll cause the block to sink; the further down it sinks, the heavier th object is. The block without any mass on top of it is half submerged, and it has a length of 2 m, a width of 2 m and a height of 5 m. If a 1200-kg mass is placed on top of the block, how far down does the block submerge from its original position, in meters? Round to the nearest hundredth (0.01), and assume the water's density is that of pure water. Justify your answer using your rationale and equations used.

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A weight scale using water can be devised using our knowledge of buoyancy. Consider the simple diagram of a
buoyed block on pure water below:
E.
The Engineering TolBox
w gleo.com
If you place an object on top of the block, it'll cause the block to sink; the further down it sinks, the heavier the
object is.
The block without any mass on top of it is half submerged, and it has a length of 2 m, a width of 2 m and a
height of 5 m.
If a 1200-kg mass is placed on top of the block, how far down does the block submerge from its original
position, in meters? Round to the nearest hundredth (0.01), and assume the water's density is that of pure
water. Justify your answer using your rationale and equations used.
Hint: Find the brick's mass using the information given, then use Newton's Second Law. The displaced volume
is equal to the cross-section area times the submerged height.
Transcribed Image Text:A weight scale using water can be devised using our knowledge of buoyancy. Consider the simple diagram of a buoyed block on pure water below: E. The Engineering TolBox w gleo.com If you place an object on top of the block, it'll cause the block to sink; the further down it sinks, the heavier the object is. The block without any mass on top of it is half submerged, and it has a length of 2 m, a width of 2 m and a height of 5 m. If a 1200-kg mass is placed on top of the block, how far down does the block submerge from its original position, in meters? Round to the nearest hundredth (0.01), and assume the water's density is that of pure water. Justify your answer using your rationale and equations used. Hint: Find the brick's mass using the information given, then use Newton's Second Law. The displaced volume is equal to the cross-section area times the submerged height.
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