A weight of mass 1.32 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.47 kg and radius 1.03 m. The system is released from rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore friction and drag forces, and assume that the string does not slip. Hint: If the string had 0 length, it would be obvious that the point mass contributes directly stuck
A weight of mass 1.32 kg is suspended by a string wrapped around a pulley wheel, which consists of a solid disk of mass 4.47 kg and radius 1.03 m. The system is released from rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore friction and drag forces, and assume that the string does not slip. Hint: If the string had 0 length, it would be obvious that the point mass contributes directly stuck
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![A weight of mass 1.32 kg is suspended by a string wrapped around a pulley wheel, which
consists of a solid disk of mass 4.47 kg and radius 1.03 m. The system is released from
rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore
friction and drag forces, and assume that the string does not slip.
Hint: If the string had 0 length, it would be obvious that the point mass contributes
Ipt = mR² to the total rotational inertia, since the point mass would be directly stuck
on the outside of the pulley. What's the difference if the string has nonzero length, so that
the point mass hangs below the pulley as in the diagram? None at all! The pulley can't tell
the difference between a point mass attached to it by a 0 length string or a 20 meter long
string. All it knows is that there's a point mass m attached to its outer edge.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F913f25bd-b2eb-4e87-8f80-5ec552fc3aee%2Fe6ba775a-a9dd-4f8e-ba71-6aa6486da47a%2F43tuvd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A weight of mass 1.32 kg is suspended by a string wrapped around a pulley wheel, which
consists of a solid disk of mass 4.47 kg and radius 1.03 m. The system is released from
rest. Over what vertical distance does the hanging mass move in 3.0 seconds? Ignore
friction and drag forces, and assume that the string does not slip.
Hint: If the string had 0 length, it would be obvious that the point mass contributes
Ipt = mR² to the total rotational inertia, since the point mass would be directly stuck
on the outside of the pulley. What's the difference if the string has nonzero length, so that
the point mass hangs below the pulley as in the diagram? None at all! The pulley can't tell
the difference between a point mass attached to it by a 0 length string or a 20 meter long
string. All it knows is that there's a point mass m attached to its outer edge.
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