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A water vapor behaves as a van der Waals gas. 1 mol of the said water vapor undergoes a process and changes for 10.00 L and 80.00°C to 20.00 L and 90°C. Solve for the AS of this process assuming that a van der Waals gas has the following equation of state. (Suppose that the heat capacity is constant.) (V – Nb)= NRT Useful values: a = 5.46x106 cm -atm/mol² b = 30.5 cm³/mol Cy.m of water at 100°C = 67.89 J/K-mol

A water vapor behaves as a van der Waals gas. 1 mol of the said water vapor undergoes a process and changes for 10.00 L and 80.00°C to 20.00 L and 90°C. Solve for the AS of this process assuming that a van der Waals gas has the following equation of state. (Suppose that the heat capacity is constant.) (V – Nb)= NRT Useful values: a = 5.46x106 cm -atm/mol² b = 30.5 cm³/mol Cy.m of water at 100°C = 67.89 J/K-mol

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A water vapor behaves as a van der Waals gas. 1 mol of the said water vapor undergoes a process and changes for 10.00 L and 80.00°C to 20.00 L and 90°C. Solve for the AS of this process assuming that a van der Waals gas has the following equation of state. (Suppose that the heat capacity is constant.) N2 (v – Nb)= NRT Useful values: a = 5.46x106 cm -atm/mol? b = 30.5 cm³/mol Cy.m of water at 100°C = 67.89 J/K-mol
Transcribed Image Text:A water vapor behaves as a van der Waals gas. 1 mol of the said water vapor undergoes a process and changes for 10.00 L and 80.00°C to 20.00 L and 90°C. Solve for the AS of this process assuming that a van der Waals gas has the following equation of state. (Suppose that the heat capacity is constant.) N2 (v – Nb)= NRT Useful values: a = 5.46x106 cm -atm/mol? b = 30.5 cm³/mol Cy.m of water at 100°C = 67.89 J/K-mol
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