During a reversible process, 457 kJ of heat is added to 0.854 kg of a certain gas while the pressure remains constant at 586 kPa. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is 26.7°C. Determine the following: (1) The universal gas rate constant for the gas is heat capacity values?) kJ/(kg-K) (Hint: How do we relate the two (2) The initial volume, V1 = m3 (Hint: If the ideal gas equation is expressed in terms of mass, it becomes PV=mRT) (3) The final volume, V2 = m3

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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During a reversible process, 457 kJ of heat is added to 0.854 kg of a certain gas while the pressure remains
constant at 586 kPa. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is
26.7°C. Determine the following:
(1) The universal gas rate constant for the gas is
heat capacity values?)
kJ/(kg-K) (Hint: How do we relate the two
(2) The initial volume, V1 :
m3 (Hint: If the ideal gas equation is expressed in terms of
%3D
mass, it becomes PV=mRT)
(3) The final volume, V2 =
m3
(4) The final temperature, T2 =
°C
(5) W =
kJ
(6) Q =
kJ
(7) DU =
kJ
(8) DH =
kJ
Transcribed Image Text:During a reversible process, 457 kJ of heat is added to 0.854 kg of a certain gas while the pressure remains constant at 586 kPa. For this gas, Cp =2.112 kJ/(kg-K) and Cv = 1.625 kJ/(kg-K). The initial temperature is 26.7°C. Determine the following: (1) The universal gas rate constant for the gas is heat capacity values?) kJ/(kg-K) (Hint: How do we relate the two (2) The initial volume, V1 : m3 (Hint: If the ideal gas equation is expressed in terms of %3D mass, it becomes PV=mRT) (3) The final volume, V2 = m3 (4) The final temperature, T2 = °C (5) W = kJ (6) Q = kJ (7) DU = kJ (8) DH = kJ
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