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A wątch purchased in 2003 for $5,680 was worth $5,260 in 2005. Assume the watch depreciated using linear model with t representing the years since 2003. (a) The linear depreciation function for the watch is D() = Number t+Number (b) How much was the worth in 2010? $ Number (c) When will the watch be worth $4,000? After Number years.

A wątch purchased in 2003 for $5,680 was worth $5,260 in 2005. Assume the watch depreciated using linear model with t representing the years since 2003. (a) The linear depreciation function for the watch is D() = Number t+Number (b) How much was the worth in 2010? $ Number (c) When will the watch be worth $4,000? After Number years.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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A watch purchased in 2003 for $5,680 was worth $5,260 in 2005. Assume the watch depreciated using linear model with t representing the years since 2003. (a) The linear depreciation function for the watch is D(t) = Number t+Number (b) How much was the worth in 2010? $ Number (c) When will the watch be worth $4,000? After Number years.
Transcribed Image Text:A watch purchased in 2003 for $5,680 was worth $5,260 in 2005. Assume the watch depreciated using linear model with t representing the years since 2003. (a) The linear depreciation function for the watch is D(t) = Number t+Number (b) How much was the worth in 2010? $ Number (c) When will the watch be worth $4,000? After Number years.
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