A W12x79 section is used as partially restrained column for a floor 8 meters high. The steel used is Grade 60 (Fy = 415 MPa). The W12x79 section has a gross cross-sectional area of 14,968 sq.mm, radius of gyration along strong axis is 133.65 mm, and radius of gyration along weak axis is 77 47 mm. Using k = 0.70, Calculate the design axial strength (KN) of the column by LRFD. The nominal compressive strength, Pn, shall be determined based on the limit state of flexural buckling. P₁ = FerAg (505.3-1) The flexural buckling stress, Fer, is determined as follows: 1. when 2. when KL r ≤ 4.71 (or F. ≥ 0.44F,) For - [0.6587|F, KL * >4.71 F (or P, <0.44P,) For=0.877F (505.3-2) (505.3-3)
A W12x79 section is used as partially restrained column for a floor 8 meters high. The steel used is Grade 60 (Fy = 415 MPa). The W12x79 section has a gross cross-sectional area of 14,968 sq.mm, radius of gyration along strong axis is 133.65 mm, and radius of gyration along weak axis is 77 47 mm. Using k = 0.70, Calculate the design axial strength (KN) of the column by LRFD. The nominal compressive strength, Pn, shall be determined based on the limit state of flexural buckling. P₁ = FerAg (505.3-1) The flexural buckling stress, Fer, is determined as follows: 1. when 2. when KL r ≤ 4.71 (or F. ≥ 0.44F,) For - [0.6587|F, KL * >4.71 F (or P, <0.44P,) For=0.877F (505.3-2) (505.3-3)
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A W12x79 section is used as partially restrained column for a floor 8 meters high. The steel used is Grade 60 (Fy = 415 MPa). The W12x79 section has a gross cross-sectional area
of 14,968 sq.mm, radius of gyration along strong axis is 133.65 mm, and radius of gyration along weak axis is 77 47 mm. Using k = 0.70, Calculate the design axial strength (KN) of
the column by LRFD.
The nominal compressive strength, Pn, shall be determined
based on the limit state of flexural buckling.
Pn= FerAg
(505-3-1)
The flexural buckling stress, Fr, is determined as follows:
1. when
2.
when
KL
r
≤ 4.71
(or F. ≥ 0.44F,)
For = [0.65872|F₂
KL
* >4.71 F (or F, <0.44F,)
For = 0.877F.
(505.3-2)
(505.3-3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F336cea7a-93af-4c56-b0f4-c8d0041a02cc%2Fd631b4d1-9152-40ab-8a81-a48b8566e236%2Fhin3dlv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A W12x79 section is used as partially restrained column for a floor 8 meters high. The steel used is Grade 60 (Fy = 415 MPa). The W12x79 section has a gross cross-sectional area
of 14,968 sq.mm, radius of gyration along strong axis is 133.65 mm, and radius of gyration along weak axis is 77 47 mm. Using k = 0.70, Calculate the design axial strength (KN) of
the column by LRFD.
The nominal compressive strength, Pn, shall be determined
based on the limit state of flexural buckling.
Pn= FerAg
(505-3-1)
The flexural buckling stress, Fr, is determined as follows:
1. when
2.
when
KL
r
≤ 4.71
(or F. ≥ 0.44F,)
For = [0.65872|F₂
KL
* >4.71 F (or F, <0.44F,)
For = 0.877F.
(505.3-2)
(505.3-3)
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