A volleyball is inflated until it has a diameter of 12 inches. How many cubic inches of air does it contain to the nearest whole cubic inch? 1) 904 2) 905 3) 7238 4) 7239

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
Question
**Example Problem for Volume Calculation**

**Problem:**

A volleyball is inflated until it has a diameter of 12 inches. How many cubic inches of air does it contain to the nearest whole cubic inch?

**Options:**
1) 904
2) 905
3) 7238
4) 7239

**Solution Explanation:**

To find the volume of the volleyball, we need to calculate the volume of a sphere since the volleyball approximates a spherical shape.

The formula for the volume \( V \) of a sphere is:

\[ V = \frac{4}{3} \pi r^3 \]

Where \( r \) is the radius of the sphere.

Given that the diameter of the volleyball is 12 inches, the radius \( r \) is half of the diameter:

\[ r = \frac{12}{2} = 6 \text{ inches} \]

Now, substituting \( r \) into the formula:

\[ V = \frac{4}{3} \pi (6)^3 \]
\[ V = \frac{4}{3} \pi (216) \]
\[ V = \frac{864}{3} \pi \]
\[ V = 288 \pi \]

Using the approximation \( \pi \approx 3.14159 \):

\[ V \approx 288 \times 3.14159 \]
\[ V \approx 904.77868 \]

To the nearest whole cubic inch, the volume is approximately:

\[ \boxed{905} \]

Therefore, the correct option is (2) 905.
Transcribed Image Text:**Example Problem for Volume Calculation** **Problem:** A volleyball is inflated until it has a diameter of 12 inches. How many cubic inches of air does it contain to the nearest whole cubic inch? **Options:** 1) 904 2) 905 3) 7238 4) 7239 **Solution Explanation:** To find the volume of the volleyball, we need to calculate the volume of a sphere since the volleyball approximates a spherical shape. The formula for the volume \( V \) of a sphere is: \[ V = \frac{4}{3} \pi r^3 \] Where \( r \) is the radius of the sphere. Given that the diameter of the volleyball is 12 inches, the radius \( r \) is half of the diameter: \[ r = \frac{12}{2} = 6 \text{ inches} \] Now, substituting \( r \) into the formula: \[ V = \frac{4}{3} \pi (6)^3 \] \[ V = \frac{4}{3} \pi (216) \] \[ V = \frac{864}{3} \pi \] \[ V = 288 \pi \] Using the approximation \( \pi \approx 3.14159 \): \[ V \approx 288 \times 3.14159 \] \[ V \approx 904.77868 \] To the nearest whole cubic inch, the volume is approximately: \[ \boxed{905} \] Therefore, the correct option is (2) 905.
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Cylinders and Cones
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning