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A vertical tube of 1m length is exposed to atmospheric steam. The mass of steam condensed per hour is 125 kg/h , calculate tube diameter ?( the wall temperature is 70 °C ) 1/4 ke°pf(Pf=Pv)g?´ |N DoHf(Th-Tw)| h = 0.725 Tf = (Th+Tw) Tw=70 °C' T, h=l atm satureted vapur Th=100 °C 1 =? Kj/kg PMA Po= =? kg/m³ RT T=? °C'de fluid properties T°C kF (W/m•C) p: (kg/m³) He (kg/ms)*104 h = 0.725[ ]/4 =, 6 W/m²K m1 = HAAT AT = (Tn – Tw) %3D 125/3600 * 1 =h * nD, * 1 * (Th – Tw) Do=? m

A vertical tube of 1m length is exposed to atmospheric steam. The mass of steam condensed per hour is 125 kg/h , calculate tube diameter ?( the wall temperature is 70 °C ) 1/4 ke°pf(Pf=Pv)g?´ |N DoHf(Th-Tw)| h = 0.725 Tf = (Th+Tw) Tw=70 °C' T, h=l atm satureted vapur Th=100 °C 1 =? Kj/kg PMA Po= =? kg/m³ RT T=? °C'de fluid properties T°C kF (W/m•C) p: (kg/m³) He (kg/ms)*104 h = 0.725[ ]/4 =, 6 W/m²K m1 = HAAT AT = (Tn – Tw) %3D 125/3600 * 1 =h * nD, * 1 * (Th – Tw) Do=? m

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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A vertical tube of 1m length is exposed to atmospheric steam. The mass of steam condensed per hour is 125 kg/h, calculate tube diameter ?( the wall temperature is 70 °C ) k°pr(Pf=Pv)g^´ |N DoHf(Th-Tw)| h = 0.725 Tf = (Th+Tw) =? Tw=70 °C' T, k=1 atm satureted vapur Th=100 °C 1=? Kj/kg PMA Pv= : =? kg/m³ RT T=? •C'de fluid properties T°C kF (W/m°C) pi (kg/m³) HE (kg/ms)*104 h = 0.725[ ]1/4 = W/m²K ma = HAAT AT = (Th – Tw) 125/3600 * A = h * nD, * 1 * (Th – Tw) Do=? m
Transcribed Image Text:A vertical tube of 1m length is exposed to atmospheric steam. The mass of steam condensed per hour is 125 kg/h, calculate tube diameter ?( the wall temperature is 70 °C ) k°pr(Pf=Pv)g^´ |N DoHf(Th-Tw)| h = 0.725 Tf = (Th+Tw) =? Tw=70 °C' T, k=1 atm satureted vapur Th=100 °C 1=? Kj/kg PMA Pv= : =? kg/m³ RT T=? •C'de fluid properties T°C kF (W/m°C) pi (kg/m³) HE (kg/ms)*104 h = 0.725[ ]1/4 = W/m²K ma = HAAT AT = (Th – Tw) 125/3600 * A = h * nD, * 1 * (Th – Tw) Do=? m
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