A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3% intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260 m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?

Q: The length of a parabolic sag curve is 126 meters. The curve's tangent grades are -2% and 3%,…

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Q: 2. An unsymmetrical parabolic curve has a forward tangent of -8% and back tangent of +5%. The length…

A: L1 = 40m L2 = 60m G1 = +5% G2 = -8% St of PC = 6 + 780 Elevation of PC = 110.1m

Q: Problem 2 A symmetrical vertical summit curve has tangents of +5% and -3%. The allowable rate of…

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Q: A 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward…

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Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Q: A vertical sag curve has a descending grade of-1.5% and an ascending grade of +3.5%. If the sag…

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