A vertical summit curve has its highest point of the curve at a distance of 48m from the PVT. The back tangent has a grade of +6% and a forward grade of -4%. The curve passes through point A on the curve at station 25+140. The elevation of the grade intersection is 100m at 25+160 Compute the length of the curve. Compute the difference in elevation between the PVI and the vertical curve elevation at midpoint of the curve. Compute the elevation of A on the curve.

Q: An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0%…

A: Solution:GradeG1=-2.0%Grade G2=1.0%Point of vertical intraction elevation=420 mPoint of vertical…

Q: A vertical curve has a back and forward tangent of +4% and -2% respectively. The vertical distance…

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Q: The tangents of a sag curve connects at the point of intersection having Station 18+407.60 and…

A: 1. Given : At point of intersection (PI) ⇒ Station = 18 + 407.60…

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

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Q: A 7% descending grade intersects an 9% ascending grade at the vertex, V, at station 1+ 100 having an…

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Q: metrical parabolic curve has a forward tangent grade of +8% and a back tangent grade of -5%. The…

A: Given:- forward tangent grade =+8% a back tangent grade of -5% tangent intersection=100m  right…

Q: A symmetrical vertical summit curve has tangents of +4.5% and -2.5%. The allowable rate of change of…

A: Question is based on the vertical summit curve . Tangents of curve,allowable rate of change of…

Q: An equal tangent sag equal tangent verticle curve (with a negative initial and a positive final…

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Q: NEED ASAP A summit curve has tangents intersects at Pl at station 14+750 with elevation of 76.30m.…

A: PVCSTATION=PVISTA-L2PVCsta=14750-3002=14+600PVCELV=PVIELV-g1L2PVCelv=76.3-0.034×3002PVCelv=71.2

Q: = An equal-tangent crest vertical curve with a length L unknown, has an initial grade is G₁ +2.5%…

A: G1 = 2.5%  G2 = -1%

Q: only need 23.2 PROBLEMS 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line…

A: The given data is shown below: Length of curve=700 ftFirst grade=4.2%Second…

Q: A symmetrical parabolic summit curve is to connect two roads with grades of +4% and -2.5% that meet…

A: G1 = 4%  G2 = -2.5%

Q: A +4% grade line intersects a -2 % grade line at station 6+800, where the elevation is 642.40 m. as…

A: When a route changes direction from right to left or its alignment changes from up to down, curves…

Q: A symmetrical Crest curve have two vertical grades intersects at station (12+80) (1 station = 100…

A: Given values, Symmetrical crest curve with vertical grades, g1= +2%, g2 = -2% Point of intersection…

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

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Q: Compute the elevation and station of the highest point of the following vertical curve. 320-m…

A: Given, L = 320 mn1 = 2 %n2 = -1.6 %

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

A: G1= -6.75% G2= 4.75%PVI station = 12+000.000 PVI elevation = 319m Station = 12 + 071.00 Elevation =…

Q: 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a-4.0% grade line.…

A: The length of curve, L= 1500 ftThe grade of upgrade, g1 = +3%The grade of downgrade, g2 = -4%The…

Q: vertical parabolic curve is to be used as a grade-separation structure. The curve is 231 m long and…

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Q: PROBLEM 1 A BACK TANGENT OF -3% WAS DESIGNED TO INTERSECT A FORWARD TANGENT OF +5% AT A PROPOSED…

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Q: A vertical parabolic curve is to be used as a grade-separation structure. The curve is 242 m long…

A: Here's the calculation: First, we need to find the parabolic constant (K) using the formula: K = (G2…

Q: 500-m long equal tangent vertical curve has a point of vertical curvature at station 2 + 600 and…

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Q: The initail and final grades of a vertical curve having 2000 ft length are 2 % (plus) and 4 %…

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Q: Problem 2 A symmetrical vertical summit curve has tangents of +5% and -3%. The allowable rate of…

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Q: A parabolic curve has a descending grade of -0.85% which meets an ascending grade of 0.35% at sta.…

A: Given Data: A parabolic curve is given as: Descending grade(g1)=-0.85%Ascending…

Q: You are required to set up a vertical curve for a highway alignment. Gradient of the backward and…

A: As per our guidelines we can solve one question only or the first three sub-parts only. If you need…

Q: Determine the elevation of point c, which is 20m away from pc(or back tangent) of a vertical sag…

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Q: A 600 ft equal tangent vertical The initial grade is -3.5% and the final grade is +0.5%. Determine…

A: L=600ft

Q: Two tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205…

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Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

A: Given : Grade of back tangent, g1 = +6% = +0.06Grade of forward tangent, g2 = -4% = -0.04Station of…

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: A 750-ft equal-tangent crest vertical curve connects tangents that intersect at elevation 572 ft.…

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Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere  Length of sag curve   Lv=1600 ftand   n1=3.5 %  and…

Q: A vertical summit vertical curve has its PVI at station 14+750 with elevation of 76.30m. The grade…

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Q: 1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the…

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