A vertical curve (with EQUAL tangent lengths) is to connect a +1.35% gradient to a -2.25% gradient on a highway designed for a speed of 80 kmph. The K value for the highway is 55 and the minimum required length is to be used. The reduced level and through chainage of the intersection point of the gradients are 78.34 metres and 667.49 metres respectively. Calculate the reduced levels and the chainages of the tangent points. Calculate the reduced levels at exact 25 metre multiples of through chainage along i) ii) the curve. iii) Calculate the through chainage and the reduced level of the highest point on the curve.
A vertical curve (with EQUAL tangent lengths) is to connect a +1.35% gradient to a -2.25% gradient on a highway designed for a speed of 80 kmph. The K value for the highway is 55 and the minimum required length is to be used. The reduced level and through chainage of the intersection point of the gradients are 78.34 metres and 667.49 metres respectively. Calculate the reduced levels and the chainages of the tangent points. Calculate the reduced levels at exact 25 metre multiples of through chainage along i) ii) the curve. iii) Calculate the through chainage and the reduced level of the highest point on the curve.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![A vertical curve (with EQUAL tangent lengths) is to connect a +1.35% gradient to a -2.25%
gradient on a highway designed for a speed of 80 kmph. The K value for the highway is 55 and
the minimum required length is to be used.
The reduced level and through chainage of the intersection point of the gradients are 78.34
metres and 667.49 metres respectively.
i)
ii)
Calculate the reduced levels and the chainages of the tangent points.
Calculate the reduced levels at exact 25 metre multiples of through chainage along
the curve.
ii)
Calculate the through chainage and the reduced level of the highest point on the
curve.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdacae8d3-e460-4074-bc39-80562f51b143%2Fdaad84cf-c65e-4b9c-8e2c-95a7a700db2d%2Fylbcsnn_processed.png&w=3840&q=75)
Transcribed Image Text:A vertical curve (with EQUAL tangent lengths) is to connect a +1.35% gradient to a -2.25%
gradient on a highway designed for a speed of 80 kmph. The K value for the highway is 55 and
the minimum required length is to be used.
The reduced level and through chainage of the intersection point of the gradients are 78.34
metres and 667.49 metres respectively.
i)
ii)
Calculate the reduced levels and the chainages of the tangent points.
Calculate the reduced levels at exact 25 metre multiples of through chainage along
the curve.
ii)
Calculate the through chainage and the reduced level of the highest point on the
curve.
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