ye height of 2.4m, a passenger car driver eye height of 1.1m, and an object height of 0.2m, calculate the minimum vertical curve length

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: A vertical curve is required for a 1st class 3x3 highway section with entering and exiting grades of…

A: The entering and exiting grades of + 5.10% and -6.40%, respectively.The point of intersection of the…

Q: 5. A compound curve is joined by two simple curves adjacent to each other, the first one having a…

A: given - compound curve is formed by joining 2 simple curve  first curve - radius = 200m, central…

Q: A horizontal curve in an urban area is being designed for 40 mph. If there is a maximum radius of…

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Q: Question 4 Topic: Gradients and Grade compensation- What is equilibrium cant required on a 5º curve…

A: Given data- Degree of curve D=5o, BG track, Speed V=60 kmph, To Find- The value of the equilibrium…

Q: An ascending grade of 4.69% meets a descending grade of -5.02% which serves as tangents for a…

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Q: A 4.5 % grade intersects a - 2.6% grade at station 1 +990 of elevation 42.30 m. Design a vertical…

A: Given data, Design speed (V) = 56kph G= 4.5%= 0.045 n= 4.5-(-2.6) = 7.1% h1=1.37m h2= 0.1m f= 0.13…

Q: A Sag curve is required to join a -4% and +4% grades.if the design speed is 100kph,determine  the…

A: Given data- Sag curve grades (n1) = -4% (n2) = +4% Design speed (V) = 100 kmph f=0.25 t = 2.5s a=…

Q: An ascending grade of 4.37% meets a descending grade of -5.33% which serves as tangents for a…

A: Stopping sight distance=115m To find length of curve

Q: Given a 520m common tangent of a compound horizontal curve, determine the length of the second curve…

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Q: An ascending grade of 4.02% meets a descending grade of -5.09% which serves as tangents for a…

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Q: tical curve is intended to connect grades of 1 45mph, determine the minimum length (ft) o to 3…

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Q: 2. Using the values given in the table, determine the maximum design speed for the following…

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Q: Given a vertical alignment connecting a -4% grade with a +2% grade with the PVC station at 34+64…

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Q: A vertical curve is required for a 1st class 3x3 highway section with entering and exiting grades of…

A: Given Data:Design speed Perception-reaction time Friction factor Entering grade: Exiting grade:…

Q: A horizontal curve on a two-lane highway is designed with a 610-m radius, 3.5-m lanes, and 80 kph…

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Q: An equal-tangent crest vertical curve is designed for 45 mi/h. The high point is at elevation 380.10…

A: Solution  Given That G1=+1.90%G2=-3.10%

Q: A trial alignment for a vertical crest curve connecting an ascending gradient of 2% with a decending…

A: Given values: Vertical crest curve: n1= +2 %, n2= -4% L= 600 m (designed) Design speed = 100 km/h

Q: A blind horizontal curve has a length equivalent to 54 meters. If the design sight distance is…

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Q: ical curve is going to be designed to join a 0% grade with a +5% grade at a section of a highway.…

A: as g1<g2curve is sag curve…

Q: While aligning a hill road with a gradient of 7%, a horizontal curve of radius 80 m is provided.…

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Q: 1. Two vertical parabolic curves have been connected to form a roadway by three gradients: -5.30 %,…

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Q: The ascending of a vertical curve is 1/45 and descending gradient is 1/55. If the design speed is 60…

A: Given: Ascending gradient, n1 = 1/45 Descending gradient, n2 = -1/55 (The negative sign is used due…

Q: True or False – Vertical Curve Design process is based on sight distance considerations.

A: Vertical curves design take sight dostance into consideration besides other factor

Q: 4. There is a vertical curve. The grade into the curve +3.2% and the grade out of the curve is…

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Q: Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990,…

A: PVI₁ (station = 4+980, Elevation = 198 m) PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃…

Q: Q3/ Given the following vertical curve data: pvl at 19+00,L-500 ft g1=+2.5%, g2= -1% and elevation…

A: Given:- The stationing of point PVI = (19+00) The length of the curve = 500 ft The initial grade of…

Q: A horizontal curve has its middle ordinate, M, 150.00 m and its external distance, E, 300.00 m. That…

A: The given data is as follows: Middle ordinate, M=150.00 mExternal distance, E=300.00 mNumber of…

Q: You are designing a vertical sag curve joining a -3% grade to a +2% grade. The design speed is 60…

A: Given: g1=-3%g2=+2% Design speedV=60 mph.

Q: A +2% grade intersects with a -1% grade at station (535-24.25) at an elevation of 300 ft. If the…

A: Solution:-Given,Elevation=300ftDesign speed=60 mi/hg1=2%g2=-1%

Q: Given a design speed of 80 kph, grades G₁ = +2%; G₂ = -2%, determine the required length of the…

A: Given : Design speed = 80 kmph.  , G1 = +2% , G2 = -2%. DETERMINE the length of curve    1. if…

Q: A vertical curve is going to be designed to join a 0% grade with a +5% grade at a section of a…

A: G1 = 0% = 0 G2 = 5% = 0.05

Q: Using a well annotated diagram, present the five point permissible approximations or assumptions…

A: Introduction- For highways and street vertical alignment, vertical curves are utilised to offer a…

Q: Given a design speed of 80 kph, grades G₁ = +2%; G₂ = -2%, determine the required length of the…

A: Given data:Design speed=80 kphG1=+2%G2=-2%N=2+2=4%N=0.04

Q: Q3: What is the minimum radius of horizontal curve for a design speed of 90 kph ?

A: Solution  Given Data V=90 kph

Q: Question 2 Field conditions require a highway curve to pass equal-tangent vertical curve and…

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Q: What is the minimum radius of horizontal curve for a design speed of 90 kph ?

A: The given data is: Design Speed (V) = 90 kmph

Q: Just do question 2

A: The "A" is the algebraic difference of the grades. As shown below.

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.