A vertical curve connected +5 % grade to a +2 % grade. The elevation of the V.P.C. is 5,150 ft. Find the elevation of the V.P.I., the high point on the curve, and the V. P.T. If you know that

Q: answer question 18 only

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Q: A 160m long parabolic curve connects a -8% grade to a +2% grade. These grades intersect at Sta.…

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Q: 23.15 A +4% grade intersects a -3% grade at station 3+ 000m at elevation 566.98 m. Compute the…

A: PVCSTATION=PVISTA-L2PVCsta=3000-6002=2+700PVCELV=PVIELV-g1L2PVCelv=566.98-0.04×6002PVCelv=554.98m

Q: What is the length of the curve, G1, highest point of curve, and the elevation of the highest point…

A: To find : Length of the curve, G1, highest point of curve, and the elevation of the highest point on…

Q: 19. What is the stationing (ft) of the EVC?

A: Length of curve, L = 1100ft  ⇒ 11 stations.   Stationing of BVC = 12+15 ft.

Q: A vertical parabolic sag curve of Laon Laan underpass has a grade of -4% followed by a grade of +2%…

A: We know that ; r = g2 - g1L L = g2 - g1r where ; g2 = 2 % = 0.02 g1 = - 4 % = - 0.04 r = 0.6 % =…

Q: A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an…

A: Given that   Sag vertical curve   g1 = -5%   g2 = 0   A = G1-G2   A = -5   PC station = (10+110)…

Q: Sketch the graph of a symmetrical parabolic curve if it has descending grade of 4% and an ascending…

A: Answer Calculation of station of PC Since we are given symmetrical parabolic curve and symmetrical…

Q: Q6. A -2.5% grade is connected to a +1.0% grade by means of a 180 m vertical curve. The P.I. station…

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Q: Vertical summit curve has tangent grades of +1.5% and - 1.5% intersecting at station 4+000 at an…

A: Given- n1=+1.5%n2=-1.5%L=182

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: -g grade of 7%. It intersects at the curve is 986 ft. ne the: elevation and station of lowe

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Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

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Q: 7.5% grade is followed by a 1.225% grade intersecting at Sta. 15+750, with an elevation of 395.5 m.…

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Q: If + 0.8% grade meets - 0.7% grade and the rate of change of grade for 30 m distance is 0.05, the…

A: g2 = -0.7% g1 = 0.8%  Rate of change of grade r= 0.05/30 = 0.00167

Q: Q 3: What is the maximum safe speed on a vertical crest

A: Given  N= +0.03(-0.03) N=0.06 Lc=200m As, S = Stopping sight distance

Q: Compute the elevation and station of the highest point of the following vertical curve. 320-m…

A: Given, L = 320 mn1 = 2 %n2 = -1.6 %

Q: A grade descending at the rate of -4% intersects another grade ascending at the rate of +8% at…

A: We have to determine the value of necessary length of the curve as per the given data in the…

Q: A – 6% grade and a 2% intersect at STA 12+200 whose elevation is at 14.375 m. The two grades are to…

A: Given data,  Sta = 12+200 Elevation of intersection = 14.375 m Grade 1 = -6% Grade = 2%

Q: A-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve…

A: This question is related to Simple curve from Surveying Engineering. In this question we calculate…

Q: elevation 400 m. Length of first curve is 180 m and that of the second curve is 120 m. What is the…

A: Given data grade, g1 =+4% grade, g2 =-2% elevation =400m Length of first curve = 180 m  Length of…

Q: You have designed a vertical crest curve which joins a +3% grade and a -4% grade. The design speed…

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Q: A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation…

A: Answer  (a) Calculation of Length of vertical curve needed to make the highest point at station 150…

Q: 26.10 A grade of +1.5% intersects a grade of -2.5% at station of 1 + 080 of elevation 68.94 m. if…

A: Given Data:g1=1.5%g2=-2.5%station=1+080Elevation=68.94m

Q: curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying…

A: Given:- 5m full station curve=10 degree 7 intermediate stations  P.C.(10+300m) To find:- Compute all…

Q: --3% grade meets a 5% grade near an underpass. In order to maintain the minimum clearance allowed…

A: Given Data-G1=-3%G2=+5%PC=10+000elevation=228Required-To determine elevation at station 10+040

Q: A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under…

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Q: you have determined the curve to be 1100 ft long. Now, you need to when the BVC is located at…

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Q: owed by a 1.25% grade intersecting at Sta. 15+750, with an elevation of 374.5 m. The change of grade…

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Q: A +3.2% grade Line meets another Line of -4% grade at station 11 + 40. If a 225-ft parabolie curve…

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Q: A +1.512% grade meets a -1.785% grade at PVI Station 31+50, elevation 562.00. The Equal Tangent…

A: Given:- The initial grade of the curve = +1.512% The final grade of the curve = -1.785% The station…

Q: For the curve above, (an equal- tangent vertical curve connects a +3.2 % and a -1.1 % grade. The PVI…

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Q: PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3%   The…

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Q: Two grade lines, SE and EA, having a slope of +4.5% and -2.8% respectively intersect at point E.…

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Q: A -6% grade and a +2% grade intersect at STA 12 + 200 whose elevation is at 25.632 m. The two grades…

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Q: A 16% grade meets a 7% grade at station 2 + 265 of elevation 250 m. The lengths are L1 = 115 m. and…

A: The grades are, g1=16%g2=7% The lengths are, L1=115 mL2=90 m The elevation is 250 m.

Q: A 400m vertical curve joins a +2.70% grade with a -1.50% grade. The PVI is at station 1+500 and…

A: To Find :- station and elevation of PVC

Q: A 400 m vertical curve connects a -2% gra grade. The P.I. is located at chainage 150 altitude of 29…

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