A vacuum tube diode consists of concentric cylindricalelectrodes, the negative cathode and the positive anode. Because of theaccumulation of charge near the cathode, the electric potential betweenthe electrodes is given by V(x) = Cx4/3 where x is the distance fromthe cathode and C is a constant, characteristic of a particular diode andoperating conditions. Assume that the distance between the cathodeand anode is 13.0 mm and the potential difference between electrodes is240 V. (a) Determine the value of C. (b) Obtain a formula for the electricfield between the electrodes as a function of x. (c) Determine the forceon an electron when the electron is halfway between the electrodes.

icon
Related questions
Question

A vacuum tube diode consists of concentric cylindrical
electrodes, the negative cathode and the positive anode. Because of the
accumulation of charge near the cathode, the electric potential between
the electrodes is given by V(x) = Cx4/3 where x is the distance from
the cathode and C is a constant, characteristic of a particular diode and
operating conditions. Assume that the distance between the cathode
and anode is 13.0 mm and the potential difference between electrodes is
240 V. (a) Determine the value of C. (b) Obtain a formula for the electric
field between the electrodes as a function of x. (c) Determine the force
on an electron when the electron is halfway between the electrodes.

Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer