A vacuum-propelled capsule for a high-speed tube transportation system of the future is being designed for operation between two stations A and B, which are 11.5 km apart. If the acceleration and deceleration are to have a limiting magnitude of 0.53g and if velocities are to be limited to 435 km/h, determine the minimum time t for the capsule to make the 11.5-km trip. 11.5 km B Answer: t = min

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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**High-Speed Tube Transportation System Capsule Analysis**

A vacuum-propelled capsule for a high-speed tube transportation system of the future is being designed for operation between two stations, named A and B, which are 11.5 km apart. The acceleration and deceleration of the capsule are to be limited to a magnitude of 0.53g. Additionally, the maximum velocity for the capsule is restricted to 435 km/h. The problem is to determine the minimum time \( t \) necessary for the capsule to travel the 11.5-km distance between the two stations.

**Illustration and Interpretation:**

The diagram illustrates the vacuum-propelled capsule on a straight track between the two stations, labeled A and B. The measured distance between the stations is shown as 11.5 km.

**Problem-Solving Approach:**

To solve this problem, we need to perform the following calculations:
1. Convert all given values to consistent units.
2. Use kinematic equations and constraints to find the time taken in different segments of the journey (acceleration, constant velocity, and deceleration).
3. Calculate the total time for the entire trip.

**Details of the Diagram:**

- The image shows the capsule within a vacuum tube. Station A is on the left, and station B is on the right.
- A horizontal line with a length of 11.5 km connects the two stations, specifying the distance between them.
- The capsule is represented as a streamlined vehicle with motion indicated by directional lines to the right toward station B.

**Required Calculation:**

Given:
- Distance = 11.5 km
- Maximum acceleration/deceleration = 0.53g (where \( g \approx 9.8 \, \text{m/s}^2 \))
- Maximum velocity = 435 km/h

The exact calculation steps and formula applications are implied in the context, which students are encouraged to follow accordingly.

Below the diagram is a box for input:
- **Answer: \( t = \) [Input Box] min**

This interactive part allows students to calculate and enter their answer based on the given constraints and their understanding of kinematic equations.

---

By following this structured approach, learners can gain a more comprehensive understanding of the dynamics involved in high-speed transportation systems and apply principles of physics to practical engineering problems.
Transcribed Image Text:**High-Speed Tube Transportation System Capsule Analysis** A vacuum-propelled capsule for a high-speed tube transportation system of the future is being designed for operation between two stations, named A and B, which are 11.5 km apart. The acceleration and deceleration of the capsule are to be limited to a magnitude of 0.53g. Additionally, the maximum velocity for the capsule is restricted to 435 km/h. The problem is to determine the minimum time \( t \) necessary for the capsule to travel the 11.5-km distance between the two stations. **Illustration and Interpretation:** The diagram illustrates the vacuum-propelled capsule on a straight track between the two stations, labeled A and B. The measured distance between the stations is shown as 11.5 km. **Problem-Solving Approach:** To solve this problem, we need to perform the following calculations: 1. Convert all given values to consistent units. 2. Use kinematic equations and constraints to find the time taken in different segments of the journey (acceleration, constant velocity, and deceleration). 3. Calculate the total time for the entire trip. **Details of the Diagram:** - The image shows the capsule within a vacuum tube. Station A is on the left, and station B is on the right. - A horizontal line with a length of 11.5 km connects the two stations, specifying the distance between them. - The capsule is represented as a streamlined vehicle with motion indicated by directional lines to the right toward station B. **Required Calculation:** Given: - Distance = 11.5 km - Maximum acceleration/deceleration = 0.53g (where \( g \approx 9.8 \, \text{m/s}^2 \)) - Maximum velocity = 435 km/h The exact calculation steps and formula applications are implied in the context, which students are encouraged to follow accordingly. Below the diagram is a box for input: - **Answer: \( t = \) [Input Box] min** This interactive part allows students to calculate and enter their answer based on the given constraints and their understanding of kinematic equations. --- By following this structured approach, learners can gain a more comprehensive understanding of the dynamics involved in high-speed transportation systems and apply principles of physics to practical engineering problems.
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