Q23. As shown in the image below, the force acting on the 2-kg crate is a function of time. The coefficient of kinetic friction between the crate and the surface is Mk= 0.16. Determine the crate's speed at t = 1.9 s if its initial speed v₁ = 1.3 m/s. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take g = 9.81 m/s². F = (201² +30) N (t in second) V1 F. 30° Your Answer: Answer units
Q23. As shown in the image below, the force acting on the 2-kg crate is a function of time. The coefficient of kinetic friction between the crate and the surface is Mk= 0.16. Determine the crate's speed at t = 1.9 s if its initial speed v₁ = 1.3 m/s. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take g = 9.81 m/s². F = (201² +30) N (t in second) V1 F. 30° Your Answer: Answer units
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Question 23**
As shown in the image below, the force acting on the 2-kg crate is a function of time. The coefficient of kinetic friction between the crate and the surface is μₖ = 0.16. Determine the crate's speed at \( t = 1.9 \) seconds if its initial speed \( v_1 = 1.3 \) m/s. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take \( g = 9.81 \) m/s².
**Equation:**
\[ F = (20t^2 + 30) \, N \quad \text{(t in seconds)} \]
**Diagram Explanation:**
The image depicts a force \( F \) acting at an angle of 30° on a crate resting on a surface. A horizontal arrow, labeled \( v_1 \), indicates the initial speed direction of the crate.
**Answer Section:**
- Your Answer: [Box for numerical entry]
- Units: [Box for unit entry]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc3def2cf-ddbd-4f44-9080-79dd92d6aea1%2F09c09d85-1344-4172-81ae-d8a7ca3e1942%2Fyewqpzk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 23**
As shown in the image below, the force acting on the 2-kg crate is a function of time. The coefficient of kinetic friction between the crate and the surface is μₖ = 0.16. Determine the crate's speed at \( t = 1.9 \) seconds if its initial speed \( v_1 = 1.3 \) m/s. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper SI unit. Take \( g = 9.81 \) m/s².
**Equation:**
\[ F = (20t^2 + 30) \, N \quad \text{(t in seconds)} \]
**Diagram Explanation:**
The image depicts a force \( F \) acting at an angle of 30° on a crate resting on a surface. A horizontal arrow, labeled \( v_1 \), indicates the initial speed direction of the crate.
**Answer Section:**
- Your Answer: [Box for numerical entry]
- Units: [Box for unit entry]
Expert Solution
Step 1
Given data
Mass of crate = 2 kg
Initial speed= 1.3 m/s
Kinetic coefficient of friction = 0.16
Find the final speed at t = 1.9 sec
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