Larson-Miller parameter =12. 10° (R-h)Rupture lifetime = 1E -4hStress = 20 MPALarson-Miller parameter =2.2. 103 (K-h)103 T(20 + log I.)(°R - h)2530354045501000800Stress = 6.9 MPA1000Stress = 1: 103 psi600100650°C400730°C200925°C815°C1008010010604010-410-310-210-11 1010210310410510Rupture lifetime (h)20103 T(20 + log I:)(K - h)Stress (MPa)Stress (10³ psi)Stress (MPa) (a) Using Animated Figure, compute the rupture lifetime for an S-590 alloy that is exposed to a tensile stress of 100 MPa at 925°C.(b) Determine the same value from the Larson-Miller plot of Animated Figure, which is for this same S-590 alloy.(a) ihours(b) ihours

(a) Using Animated Figure, compute the rupture lifetime for an S-590 alloy that is exposed to a tensile stress of 100 MPa at 925°C. (b) Determine the same value from the Larson-Miller plot of Animated Figure, which is for this same S-590 alloy.

(a) Using Animated Figure, compute the rupture lifetime for an S-590 alloy that is exposed to a tensile stress of 100 MPa at 925°C. (b) Determine the same value from the Larson-Miller plot of Animated Figure, which is for this same S-590 alloy.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Larson-Miller parameter =
12. 10° (R-h)
Rupture lifetime = 1E -4h
Stress = 20 MPA
Larson-Miller parameter =
2.2. 103 (K-h)
103 T(20 + log I.)(°R - h)
25
30
35
40
45
50
1000
800
Stress = 6.9 MPA
1000
Stress = 1: 103 psi
600
100
650°C
400
730°C
200
925°C
815°C
100
80
100
10
60
40
10-4
10-3
10-2
10-1
1 10
102
103
104
105
10
Rupture lifetime (h)
20
103 T(20 + log I:)(K - h)
Stress (MPa)
Stress (10³ psi)
Stress (MPa)

(a) Using Animated Figure, compute the rupture lifetime for an S-590 alloy that is exposed to a tensile stress of 100 MPa at 925°C.
(b) Determine the same value from the Larson-Miller plot of Animated Figure, which is for this same S-590 alloy.
(a) i
hours
(b) i
hours

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