A unigram is a sequence of words of length one (i.e. a single word). • A bigram is a sequence of words of length two. • The conditional probability of an event E2 given another event E1, written p(E2|E1), is the probability that E2 will occur given that event E1 has already occurred. We write p(w(k)|w(k-1)) for the conditional probability of a word w in position k, w(k), given the immediately preceding word, w(k-1). You determine the conditional probabilities by determining unigram counts (the number of times each word appears, written c(w(k)), bigram counts (the number of times each pair of words appears, written c(w(k-1) w(k)), and then dividing each bigram count by the unigram count of the first word in the bigram: p(WORD(k)|WORD(k-1)) = c(WORD(k-1) WORD(k)) / c(WORD(k-1)) Apply and incorporate instrutions to code below. #include //including headers #include #include struct node{//structure intialization int data; struct node *next; }; #include   typedef struct Info_ { char name[100]; } Info;   typedef struct Compar_ { Info info; struct Compar_* next; } Compar;   void print_comparisons(Compar* CP)//comparison method { assert(CP);   Compar* cur = CP; Compar* next = cur->next; for (; next; cur = next, next = next->next) { if (strcmp(cur->info.name, next->info.name) == 0) printf("Same name\n"); else printf("Diff name\n"); } } struct node *head, *tail = NULL; void addNode(int data) {//adding node method struct node *newNode = (struct node*)malloc(sizeof(struct node)); newNode->data = data; newNode->next = NULL;   if(head == NULL) { head = newNode; tail = newNode; } else { tail->next = newNode;   tail = newNode; } }   void removeDuplicate() {//duplicate method definition   struct node *current = head, *index = NULL, *temp = NULL;   if(head == NULL) { return; } else { while(current != NULL){   temp = current;   index = current->next;   while(index != NULL) {   if(current->data == index->data) {   temp->next = index->next; } else {   temp = index; } index = index->next; } current = current->next; } } }   void display() {   struct node *current = head; if(head == NULL) { printf("List is empty \n"); return; } while(current != NULL) {   printf("%d ", current->data); current = current->next; } printf("\n"); }   struct node* findMiddle(struct node* b, struct node* e) { if(b == NULL) return NULL; struct node* slow = b; struct node* fast = b->next; while(fast != e) { fast=fast->next; if(fast != e) { slow = slow->next; fast = fast->next; } } return slow; };   struct node* binarysearch(int searchItem) { struct node* beg = head; struct node* end = NULL; do { struct node* middle = findMiddle(beg, end); if(middle == NULL) return middle; else if(middle->data == searchItem) return middle; else if(middle->data < searchItem) beg = middle->next; else end = middle; }while(end==NULL || end != beg); return NULL; }   int main()//main method {   addNode(1); addNode(2); addNode(3); addNode(2); addNode(2); addNode(4); addNode(1);   printf("Originals list: \n"); display();   printf("================"); removeDuplicate();   printf("List after removing duplicates: \n"); display();   printf("Search for 3 in the linked list:\n"); struct node* n = binarysearch(3); if(n==NULL) { printf("Item not Found\n"); } else { printf("Item Found\n"); printf("%d\n",n->data); } printf("Search for 7 in the linked list:\n"); n = binarysearch(7); if(n==NULL) { printf("Item not Found\n"); } else { printf("Item Found\n"); printf("%d",n->data); } printf("================"); Info a; a.name[0] = 'A'; a.name[1] = '\0'; Info b; b.name[0] = 'B'; b.name[1] = '\0'; Info c; c.name[0] = 'B'; c.name[1] = '\0'; Info d; d.name[0] = 'D'; d.name[1] = '\0'; Compar na; na.info = a; Compar nb; nb.info = b; Compar nc; nc.info = c; Compar nd; nd.info = d;   na.next = &nb; nb.next = &nc; nc.next = &nd; nd.next = NULL;   print_comparisons(&na); return 0; }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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A unigram is a sequence of words of length one (i.e. a single word).
• A bigram is a sequence of words of length two.
• The conditional probability of an event E2 given another event E1, written
p(E2|E1), is the probability that E2 will occur given that event E1 has already
occurred.
We write p(w(k)|w(k-1)) for the conditional probability of a word w in position k,
w(k), given the immediately preceding word, w(k-1). You determine the conditional
probabilities by determining unigram counts (the number of times each word
appears, written c(w(k)), bigram counts (the number of times each pair of words
appears, written c(w(k-1) w(k)), and then dividing each bigram count by the
unigram count of the first word in the bigram:
p(WORD(k)|WORD(k-1)) = c(WORD(k-1) WORD(k)) / c(WORD(k-1))

Apply and incorporate instrutions to code below.

#include <stdio.h>//including headers
#include <string.h>
#include <stdlib.h>

struct node{//structure intialization

int data;

struct node *next;

};

#include <assert.h>

 

typedef struct Info_ {

char name[100];

} Info;

 

typedef struct Compar_ {

Info info;

struct Compar_* next;

} Compar;

 

void print_comparisons(Compar* CP)//comparison method

{

assert(CP);

 

Compar* cur = CP;

Compar* next = cur->next;

for (; next; cur = next, next = next->next) {

if (strcmp(cur->info.name, next->info.name) == 0)

printf("Same name\n");

else

printf("Diff name\n");

}

}


struct node *head, *tail = NULL;


void addNode(int data) {//adding node method


struct node *newNode = (struct node*)malloc(sizeof(struct node));

newNode->data = data;

newNode->next = NULL;

 

if(head == NULL) {


head = newNode;

tail = newNode;

}

else {


tail->next = newNode;

 

tail = newNode;

}

}

 

void removeDuplicate() {//duplicate method definition

 

struct node *current = head, *index = NULL, *temp = NULL;

 

if(head == NULL) {

return;

}

else {

while(current != NULL){

 

temp = current;

 

index = current->next;

 

while(index != NULL) {

 

if(current->data == index->data) {

 

temp->next = index->next;

}

else {

 

temp = index;

}

index = index->next;

}

current = current->next;

}

}

}

 

void display() {

 

struct node *current = head;

if(head == NULL) {

printf("List is empty \n");

return;

}

while(current != NULL) {

 

printf("%d ", current->data);

current = current->next;

}

printf("\n");

}

 

struct node* findMiddle(struct node* b, struct node* e)

{

if(b == NULL)

return NULL;

struct node* slow = b;

struct node* fast = b->next;

while(fast != e)

{

fast=fast->next;

if(fast != e)

{

slow = slow->next;

fast = fast->next;

}

}

return slow;

};

 

struct node* binarysearch(int searchItem)

{

struct node* beg = head;

struct node* end = NULL;

do

{

struct node* middle = findMiddle(beg, end);

if(middle == NULL)

return middle;

else if(middle->data == searchItem)

return middle;

else if(middle->data < searchItem)

beg = middle->next;

else

end = middle;

}while(end==NULL || end != beg);

return NULL;

}

 

int main()//main method

{

 

addNode(1);

addNode(2);

addNode(3);

addNode(2);

addNode(2);

addNode(4);

addNode(1);

 

printf("Originals list: \n");

display();

 

printf("================");

removeDuplicate();

 

printf("List after removing duplicates: \n");

display();

 

printf("Search for 3 in the linked list:\n");

struct node* n = binarysearch(3);

if(n==NULL)

{

printf("Item not Found\n");

}

else

{

printf("Item Found\n");

printf("%d\n",n->data);

}

printf("Search for 7 in the linked list:\n");

n = binarysearch(7);

if(n==NULL)

{

printf("Item not Found\n");

}

else

{

printf("Item Found\n");

printf("%d",n->data);

}

printf("================");

Info a; a.name[0] = 'A'; a.name[1] = '\0';

Info b; b.name[0] = 'B'; b.name[1] = '\0';

Info c; c.name[0] = 'B'; c.name[1] = '\0';

Info d; d.name[0] = 'D'; d.name[1] = '\0';

Compar na; na.info = a;

Compar nb; nb.info = b;

Compar nc; nc.info = c;

Compar nd; nd.info = d;

 

na.next = &nb;

nb.next = &nc;

nc.next = &nd;

nd.next = NULL;

 

print_comparisons(&na);

return 0;

}

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