A uniformly charged insulating rod of length 16.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -6.50 µC. Find the electric potential at O, the center of the semicircle. MV •0

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A uniformly charged insulating rod of length 16.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod
has a total charge of -6.50 µC. Find the electric potential at O, the center of the semicircle.
MV
Transcribed Image Text:A uniformly charged insulating rod of length 16.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -6.50 µC. Find the electric potential at O, the center of the semicircle. MV
Expert Solution
Step 1

Given:

length of rod, l = 16 cm

charge, q = -6.50 μC = -6.50×10-6C

 

Solution:

Consider the length, 

L = π r

Re-arranging and substituting the values to solve for r, we get:

r = 0.16π m

 

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