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A uniform symmetrical beam is supported at two pin joints as shown below. It has a length L and a uniformly distributed load P: (x) = p is applied. The maximum bending moment M, (x) will be half way along the beam.

A uniform symmetrical beam is supported at two pin joints as shown below. It has a length L and a uniformly distributed load P: (x) = p is applied. The maximum bending moment M, (x) will be half way along the beam.

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A uniform symmetrical beam is supported at two pin joints as shown below. It has a length L and a uniformly distributed load P: (x) = p is applied. The maximum bending moment My (x) will be half way along the beam. If the length L is 9.1 m, and the distributed load P is 434 N/m, then calculate the value of My (x) at the mid-point.
Transcribed Image Text:A uniform symmetrical beam is supported at two pin joints as shown below. It has a length L and a uniformly distributed load P: (x) = p is applied. The maximum bending moment My (x) will be half way along the beam. If the length L is 9.1 m, and the distributed load P is 434 N/m, then calculate the value of My (x) at the mid-point.
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