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A uniform stress of 250 KPa is applied to the loaded area shown below: Using Newmark chart, compute the stress at a depth of 80 m below the ground surface due to the loaded area under point O'.

A uniform stress of 250 KPa is applied to the loaded area shown below: Using Newmark chart, compute the stress at a depth of 80 m below the ground surface due to the loaded area under point O'.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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EXAMPLES 1 Solution A uniform stress of 250 KPa is applied to the loaded area shown below: (Dimensions in meters) Using Newmark chart, compute the stress at a depth of 80 m below the ground surface due to the loaded area under point O'. Uniform lead, 250 KP Scale I em-20 m ot 40 60 Draw the loaded area such that the length of the line OQ is scaled to 80m. For exanple. the ilist ance ĀB in Fig. Ex. 8.3a is 1.5 times the distance OQ.0Q = 80 m and AB - 120 m. Next, place point O', the point where the stress is required, over the center of the influence chart (as shown in Fig. Ex. 8.3b to a slightly smaller scale). The number of blocks (and partial blocks) are counted under the loaded area. In this case, about eight blocks are found. The vertical stress at 80 m is then indicated by: (a) Influence o,- qdxNo. of blocks bleck-0.02 Where q.- surface or contact stress, and 1 - influence value per block (0.02 in Fig. Ex. 8.3b) Therefore, o,- 250 KPax0.02x8 blocks = 40 KPa Deph pre To compute the stress at other depths, the process is repeated by making other drawings for the different depths, changing the scale each time to correspond to the distance OQ on the influence chart. (b) Figure Ex 83 (ler Newmark, 1942)
Transcribed Image Text:EXAMPLES 1 Solution A uniform stress of 250 KPa is applied to the loaded area shown below: (Dimensions in meters) Using Newmark chart, compute the stress at a depth of 80 m below the ground surface due to the loaded area under point O'. Uniform lead, 250 KP Scale I em-20 m ot 40 60 Draw the loaded area such that the length of the line OQ is scaled to 80m. For exanple. the ilist ance ĀB in Fig. Ex. 8.3a is 1.5 times the distance OQ.0Q = 80 m and AB - 120 m. Next, place point O', the point where the stress is required, over the center of the influence chart (as shown in Fig. Ex. 8.3b to a slightly smaller scale). The number of blocks (and partial blocks) are counted under the loaded area. In this case, about eight blocks are found. The vertical stress at 80 m is then indicated by: (a) Influence o,- qdxNo. of blocks bleck-0.02 Where q.- surface or contact stress, and 1 - influence value per block (0.02 in Fig. Ex. 8.3b) Therefore, o,- 250 KPax0.02x8 blocks = 40 KPa Deph pre To compute the stress at other depths, the process is repeated by making other drawings for the different depths, changing the scale each time to correspond to the distance OQ on the influence chart. (b) Figure Ex 83 (ler Newmark, 1942)
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