A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by 1/3(ML^2). If a force (F = 5.0 N, q = 40°) acts as shown, what is the resulting angular acceleration about the pivot point? K Pivot 33 rad/s² O 10 rad/s² 14 rad/s² 16 rad/s² O 12 rad/s² p q# 6 p. 242 chap 7

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A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless
horizontal plane, is free to pivot about a vertical axis through one end, as shown.
The moment of inertia of the rod about this axis is given by 1/3(ML^2). If a force (F
= 5.0 N, q = 40°) acts as shown, what is the resulting angular acceleration about
the pivot point?
K
Pivot
33 rad/s²
O 10 rad/s²
14 rad/s²
16 rad/s²
O 12 rad/s²
p q# 6 p. 242 chap
7
Transcribed Image Text:A uniform rod of mass M = 1.2 kg and length L = 0.80 m, lying on a frictionless horizontal plane, is free to pivot about a vertical axis through one end, as shown. The moment of inertia of the rod about this axis is given by 1/3(ML^2). If a force (F = 5.0 N, q = 40°) acts as shown, what is the resulting angular acceleration about the pivot point? K Pivot 33 rad/s² O 10 rad/s² 14 rad/s² 16 rad/s² O 12 rad/s² p q# 6 p. 242 chap 7
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