A uniform electric field is oriented in the -z direction. The magnitude of the electric field is 6500 N/C.(a) How will the equipotential surfaces associated with this electric field be oriented?O parallel to the xy planeO parallel to the xz planeO parallel to the yz plane(b) Consider two of the equipotential surfaces; one with a potential of 13 V and the other with a potential of -20 V. What is the separation between these two surfaces?0.00108How is electric field related to the potential difference across a certain distance? mm

The relation between potential difference and electric field is given as V = Ed V is potential…

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