A uniform disk with radius 0.800 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to 0(t) = (1.10 rad/s)t + (6.30 rad/s²)t². Part A What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned through 0.100 rev? Express your answer with the appropriate units. a = 1 Value Units ?

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Chapter1: Units, Trigonometry. And Vectors
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A uniform disk with radius 0.800 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axle
that passes through the center of the disk. The angle through which the disk has turned varies with time according
to 0(t) = (1.10 rad/s)t + (6.30 rad/s²)t².
Part A
What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned
through 0.100 rev?
Express your answer with the appropriate units.
a =
μA
Value
Submit
Request Answer
=
Units
?
Transcribed Image Text:A uniform disk with radius 0.800 m and mass 30.0 kg rotates in a horizontal plane on a frictionless vertical axle that passes through the center of the disk. The angle through which the disk has turned varies with time according to 0(t) = (1.10 rad/s)t + (6.30 rad/s²)t². Part A What is the resultant linear acceleration of a point on the rim of the disk at the instant when the disk has turned through 0.100 rev? Express your answer with the appropriate units. a = μA Value Submit Request Answer = Units ?
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