A two-way ANOVA experiment with no Interaction is conducted. Factor A has four levels (columns) and Factor B has seven levels (rows). Assume normality in the underlying populations. The results include the following sum of squares terms: SST=321.6 SSA=154.0 SSE = 65.2 a. Construct an ANOVA table. (Round "SS" and "MS" to 2 decimal places and "P" to 3 decimal places.) ANOVA Source of Variation Rows Columns | Error Total SS df No, since we do not reject the null hypothesis. O Yes, since we do not reject the null hypothesis. O No, since we reject the null hypothesis. O Yes, since we reject the null hypothesis. MS b. At the 1% significance level, can you conclude that the row means differ? F O Yes, since we reject the null hypothesis. O No, since we reject the null hypothesis. O Yes, since we do not reject the null hypothesis. O No, since we do not reject the null hypothesis. c. At the 1% significance level, can you conclude that the column means differ? p-value 0.005 0.000

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A two-way ANOVA experiment with no Interaction is conducted. Factor A has four levels (columns) and Factor B has seven levels
(rows). Assume normality in the underlying populations. The results include the following sum of squares terms:
SST=321.6 SSA = 154.0 SSE = 65.2
a. Construct an ANOVA table. (Round "SS" and "MS" to 2 decimal places and "P" to 3 decimal places.)
ANOVA
Source of Variation
Rows
Columns
Error
Total
SS
df
No, since we do not reject the null hypothesis.
Yes, since we do not reject the null hypothesis.
O No, since we reject the null hypothesis.
Yes, since we reject the null hypothesis.
b. At the 1% significance level, can you conclude that the row means differ?
MS
Yes, since we reject the null hypothesis.
No, since we reject the null hypothesis.
F
c. At the 1% significance level, can you conclude that the column means differ?
Yes, since we do not reject the null hypothesis.
No, since we do not reject the null hypothesis.
p-value
0.005
0.000
Transcribed Image Text:A two-way ANOVA experiment with no Interaction is conducted. Factor A has four levels (columns) and Factor B has seven levels (rows). Assume normality in the underlying populations. The results include the following sum of squares terms: SST=321.6 SSA = 154.0 SSE = 65.2 a. Construct an ANOVA table. (Round "SS" and "MS" to 2 decimal places and "P" to 3 decimal places.) ANOVA Source of Variation Rows Columns Error Total SS df No, since we do not reject the null hypothesis. Yes, since we do not reject the null hypothesis. O No, since we reject the null hypothesis. Yes, since we reject the null hypothesis. b. At the 1% significance level, can you conclude that the row means differ? MS Yes, since we reject the null hypothesis. No, since we reject the null hypothesis. F c. At the 1% significance level, can you conclude that the column means differ? Yes, since we do not reject the null hypothesis. No, since we do not reject the null hypothesis. p-value 0.005 0.000
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