A two-tailed test at a 0.1031 level of significance has z values of a. -1.63 and 1.63 O b. -0.82 and 0.82 Oc.-0.82 and 0.82 Od. -1.26 and 1.26 Show All Feedback
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- A random sample of n1 = 55 stemmed projectile points showed the mean length to be x1 = 3.00 cm, with sample standard deviation s1 = 0.80 cm. Another random sample of n2 = 46 stemless projectile points showed the mean length to be x2 = 2.70 cm, with s2 = 0.90 cm. Do these data indicate a difference (either way) in the population mean length of the two types of projectile points? Use a 5% level of significance.What are we testing in this problem? A or b? A.difference of proportionsdifference of means b. paired differencesingle meansingle proportion What is the level of significance?State the null and alternate hypotheses, which one? a.H0: ?1 ≠ ?2; H1: ?1 = ?2 B.H0: ?1 ≤ ?2; H1: ?1 > ?2 C. H0: ?1 = ?2; H1: ?1 ≠ ?2 D.H0: ?1 ≥ ?2; H1: ?1 < ?2 What sampling distribution will you use? What assumptions are you making? a.The standard normal. We assume that both population distributions are approximately normal with known population standard deviations. b.The Student's t. We assume…In a sample of 14 randomly selected high school seniors, the mean score on a standardized test was 1181 and the standard deviation was 162.1. Further research suggests that the population mean score on this test for high school seniors is 1019. Does the t-value for the original sample fall between −t0.99 and t0.99? Assume that the population of test scores for high school seniors is normally distributed.A product comes in cans labeled "38 oz". A random sample of 10 cans had the following weights: {34.6, 39.65, 34.75, 40, 39.5, 38.9, 34.25, 36.8, 39, 37.2} with the following R output: One Sample t-testdata: productt = 52.299, df = 9, p-value = 1.716e-12alternative hypothesis: true mean is not equal to 095 percent confidence interval: 35.84448 39.08552sample estimates:mean of x 37.465 Using the provided output, estimate the true mean weight of the cans of product with 95% confidence a. 35.8, 39.1 ounces b. 34, 41 ounces c. 37.465 ounces d. 36.1, 38.9 ounces
- A company manufactures tennis balls. When its tennis balls are dropped onto a concrete surface from a height of 100 inches, the company wants the mean height the balls bounce upward to be 55.2 inches. This average is maintained by periodically testing random samples of 25 tennis balls. If the t-value falls between −t0.95 and t0.95, then the company will be satisfied that it is manufacturing acceptable tennis balls. A sample of 25 balls is randomly selected and tested. The mean bounce height of the sample is 56.1 inches and the standard deviation is 0.25 inch. Assume the bounce heights are approximately normally distributed. Is the company making acceptable tennis balls? Find −t0.95 and t0.95.A random sample of 15 families representing three different Scandinavian countries has been observed for the number of weekend trips they take per year. Are the differences significant (use p=.05, F(critical) = 3.88)? Use the five step model as a guide and write a sentence or two of interpretation for your results. Sweden Norway Denmark 10 11 7 9 10 5 4 5 2 2 2 0Identify Ho and Ha for a paired t-test to determine if there is a difference in the number of breeding horseshoe crabs from 2011 to 2012: The mean difference between paired observations is zero. The mean difference between paired observations is not zero. Use the paired t-test function (=ttest(array1, array2, tails, type) to determine the if the two sets of measurements are correlated with each other. Report your answer to three decimal places. Do you fail to reject or reject the null hypothesis? Were the number of breeding horseshoe crabs the same or different between between the two years?
- If P(A) = 0.52, P(B) = 0.45 and P(A u B) = 0.76, then P(B | A) = (Enter a number between 0 and 1, using two decimal points)The lowest level of significance to reject the null hypothesis of no linear association between blood pressure and age is: OA: 0.003 OB: 0.05 OC: 0.0002 OD: 0.0001 OE: 0.04When should the Wilcoxon Signed-Ranks Test be used instead of the paired t-test?
- A researcher reports t(22) = 5.30, p <.01 for an independent-measures research. How many individuals participated in the entire experiment?A company manufactures tennis balls. When its tennis balls are dropped onto a concrete surface from a height of 100 inches, the company wants the mean height the balls bounce upward to be 54.8 inches. This average is maintained by periodically testing random samples of 25 tennis balls. If the t-value falls between −t0.98 and t0.98, then the company will be satisfied that it is manufacturing acceptable tennis balls. A sample of 25 balls is randomly selected and tested. The mean bounce height of the sample is 56.6 inches and the standard deviation is 0.25 inch. Assume the bounce heights are approximately normally distributed. Is the company making acceptable tennis balls? Find −t0.98 and t0.98. −t0.98 = t0.98= Find the t-valueA company manufactures tonnis balls. When its tennis balls are dropped onto a concrete surface from a height of 100 inches, the company wants the mean height the balls bounce upward to be 54.7 inches. This average is maintained by periodically testing random samples of 25 tennis balls. If the t-value falls between -to ak and t as then the company will be satisfied that it is manufacturing acceptable tennis balls. A sample of 25 balls is randomly selected and tested. The mean bounce height of the sample is 56.8 inches and the standard deviation is 0.25 inch. Assume the bounce heights are approximately normally distributed. Is the company making acceptable tennis balls? Find -th os and to 96- -to.96 = 0.96 = (Round to three decimal places as needed.)
