(a) Two capacitors, C, - 5.58 µF and C, - 3.02 pf, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in pC)? d'. - 415 225
(a) Two capacitors, C, - 5.58 µF and C, - 3.02 pf, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in pC)? d'. - 415 225
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:(a) Two capacitors, C, = 5.58 µF and C, = 3.02 pF, are connected in parallel, then the combination is connected to a 250 V battery. When the capacitors are charged, each one is removed from the circuit. Next, the two charged capacitors are connected to each other so that the positive plate of one
capacitor is connected to the negative plate of the other capacitor. What is the resulting charge on each capacitor (in pC)?
q', -
415
v µC
q', = 225
V µC
(b) What If? What is the resulting charge on each capacitor (in µC) if they are instead charged as a series combination and then connected positive plate to positive plate and negative plate to negative plate?
q', = 418.5E-6
Note that when the two capacitors are connected again in the new configuration, the total charge redistributes itself so that the voltages across the capacitors are equal. pc
q', = 226.5E-6
Note that when the two capacitors are connected again in the new configuration, the total charge redistributes itself so that the voltages across the capacitors are equal. pc
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