A turning operation is made with a tool tilted 10° from the normal to the workpeice axis of rotation and the tool has a rake angle of 20°, and a depth of cut = 1mm. The shear strength of the work material is known to be 345 MPa, the coefficient of friction is 1.2, the chip thickness is measured after the cut to be 2.5 mm, and the cutting speed is 1000 mm/sec. As a production engineer you have been asked to set a value for i) Cutting Forces ii) estimate the power dissipated in friction and iii) estimate the specific energy. Assume width of cut to be 3 mm Hint: shear force = shear strength shear area, shear area depth of cut/ sin (shear angle)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A turning operation is made with a tool tilted 10° from the normal to the workpeice axis of
rotation and the tool has a rake angle of 20°, and a depth of cut = 1mm. The shear strength of
the work material is known to be 345 MPa, the coefficient of friction is 1.2, the chip thickness
is measured after the cut to be 2.5 mm, and the cutting speed is 1000 mm/sec. As a
production engineer you have been asked to set a value for i) Cutting Forces ii) estimate
the power dissipated in friction and iii) estimate the specific energy.
Assume width of cut to be 3 mm
shear area= depth of cut/ sin (shear angle)
Hint: shear force = shear strength * shear area,
Use effective rake angle instead of rake angle
Transcribed Image Text:A turning operation is made with a tool tilted 10° from the normal to the workpeice axis of rotation and the tool has a rake angle of 20°, and a depth of cut = 1mm. The shear strength of the work material is known to be 345 MPa, the coefficient of friction is 1.2, the chip thickness is measured after the cut to be 2.5 mm, and the cutting speed is 1000 mm/sec. As a production engineer you have been asked to set a value for i) Cutting Forces ii) estimate the power dissipated in friction and iii) estimate the specific energy. Assume width of cut to be 3 mm shear area= depth of cut/ sin (shear angle) Hint: shear force = shear strength * shear area, Use effective rake angle instead of rake angle
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